Re: Simple question from a biologist

*To*: mathgroup at smc.vnet.net*Subject*: [mg67159] Re: [mg67139] Simple question from a biologist*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Sun, 11 Jun 2006 02:17:20 -0400 (EDT)*Reply-to*: hanlonr at cox.net*Sender*: owner-wri-mathgroup at wolfram.com

Sol = Solve[{ {{-x,0,z},{x,-y,0},{0,y,-z}}.{A,B,C}==0, A + B + C == 1}, {A, B, C}][[1]]; where [[1]] is used to strip the outer brackets rate=A*x/.Sol (x*y*z)/(x*y + z*y + x*z) (A*x==B*y==C*z)/.Sol True Bob Hanlon ---- tnad <terry_najdi at hotmail.com> wrote: > I'm a bit new to this so please bear with me. I solved this eqation: > > Sol = Solve[{{{-x, 0, z}, {x, -y, 0}, {0, y, -z}}.{A, B, C} == 0, A + B + C == 1}, {A, B, C}] > > and got the ouputs of A, B and C interms of x,y, and z each. > > Now I want to express a term called "rate" where rate = Ax = By = Cz in terms of x, y and Z only. > > So I tried to do this: > Solve[rate == Ax , rate] /. Sol > > but I cannot get the rate in terms of x,y and z. > Is there a better way to do this? Also if someone knows of a better tuttorial (better than the built-in tuttorial) for mathematica, please let me know. > -- Bob Hanlon hanlonr at cox.net