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MathGroup Archive 2006

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Re: a list as an option

  • To: mathgroup at
  • Subject: [mg67191] Re: a list as an option
  • From: Peter Pein <petsie at>
  • Date: Sun, 11 Jun 2006 23:07:54 -0400 (EDT)
  • References: <e6gd7r$n9j$>
  • Sender: owner-wri-mathgroup at

Akane Tendo schrieb:
> Hello,
> If I have a function f with options like:
> Options[f]=[...,{pars->{a,b,c}}]

You should get an error message, when trying this (don't know, why you didn't get it).
Assign a list of rules to Options[f]:

Options[f] = {pars -> {a, b, c}};

> How can I change just one of 'pars' options ('a', 'b' or 'c')?
> I tried to change, for example, 'a' to 'd' like this:
> SetOptions[f,pars[[1]]->d]

SetOptions[f, (Options[f, pars] /. a -> d)[[1]]];

or, if you want to replace the first element of the list, no matter what it is:

SetOptions[f, ReplacePart[Options[f, pars], numberone, {1, 2, 1}][[1]]]

> But it didn't work.
> I also tried to access the option:
> Options[f,pars]
> And the result is: {}

Caused by the syntax error above, there has not been any assignment to Options[f].

> Does anyone know what am I doing wrong or if it's not possible at all to 
> have a list as an option?
> Thank you!! 

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