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MathGroup Archive 2006

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Re: Interrogating lists of unequal lenghths

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67376] Re: [mg67367] Interrogating lists of unequal lenghths
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Wed, 21 Jun 2006 02:12:29 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

dim[x_]:=If[Equal@@(Length/@x),Dimensions[x],
      {Length[x],Length/@x}];

y={{1,2},{3,4},{5,6}};

dim[y]

{3,2}

x={{1},{2,3},{4,5,6,7}};

dim[x]

{3,{1,2,4}}


Bob Hanlon

---- kevin_jazz <kevinbowman at mac.com> wrote: 
> I'm trying to understand how to assess the dimensions of a list
> containing elements of unequal length.
> Let's say I have the list with elements of equal sizes
> 
> In[12]:=
> y={{1,2},{3,4},{5,6}}
> 
> Out[12]=
> {{1,2},{3,4},{5,6}}
> 
> In[13]:=
> Dimensions[y]
> 
> Out[13]=
> {3,2}
> 
> Using the Dimensions function I can determine the size of the resulting
> array. If, on the other hand, I set up the following list
> 
> In[5]:=
> x={{1},{2,3},{4,5,6,7}}
> 
> In[6]:=
> Dimensions[x]
> 
> Out[6]=
> {3}
> 
> The Dimensions command tells me I have only 3 elements.  But, I need
> some way to figure out that the first sublist has length 1, second has
> length 2, and the third has length 4 in some automated fashion. I've
> looked through the other commands like Depth and Length but I don't see
> anything that does this. 
> 
> What's the right to do it? 
> 
> Thanks,
> 
> Kevin
> 


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