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MathGroup Archive 2006

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preclude mathematical meaning of OverBar etc

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67382] preclude mathematical meaning of OverBar etc
  • From: Martin Schoenecker <ms_usenet at gmx.de>
  • Date: Wed, 21 Jun 2006 02:12:47 -0400 (EDT)
  • Organization: Technische Universitaet Darmstadt
  • Sender: owner-wri-mathgroup at wolfram.com

Dear group,

I would like to use OverBar, SuperStar etc. to define characteristic or 
modified values for the same, "plain" variable.  Unfortunately, as every 
expression, they become a mathematical meaning which is not what I 
intend, e.g. for a substitution:

test

In[19]:=
subsfun = u -> Function[{x, t},
     OverHat[l]*OverTilde[u][
       OverTilde[x][x], OverTilde[t][
        t]]]
subsvar = OverTilde[t] ->
    Function[t, t/OverHat[t]]
resubsvar = t/OverHat[t] ->
    OverTilde[t]

Out[19]=
u -> Function[{x, t}, OverHat[l]*
     OverTilde[u][OverTilde[x][x],
      OverTilde[t][t]]]

Out[20]=
OverTilde[t] -> Function[t,
    t/OverHat[t]]

Out[21]=
t/OverHat[t] -> OverTilde[t]

In[22]:=
D[u[x, t], t]
% /. subsfun
% /. subsvar
% /. resubsvar

Out[22]=
Derivative[0, 1][u][x, t]

Out[23]=
OverHat[l]*Derivative[1][
     OverTilde[t]][t]*
   Derivative[0, 1][OverTilde[u]][
    OverTilde[x][x], OverTilde[t][t]]

Out[24]=
OverHat[l]*(1/OverHat[t] -
    (t*Derivative[1][OverHat][t])/
     OverHat[t]^2)*
   Derivative[0, 1][OverTilde[u]][
    OverTilde[x][x], t/OverHat[t]]

Out[25]=
OverHat[l]*(1/OverHat[t] -
    (t*Derivative[1][OverHat][t])/
     OverHat[t]^2)*
   Derivative[0, 1][OverTilde[u]][
    OverTilde[x][x], OverTilde[t]]

where I get the derivative of the OverHat term, which is not desired. 
How to overcome this?  Is there another possibility than to use 
Symbolize with Utilities`Notation`?  Thanks for any hints,

Martin


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