Re: Integrate with multiple integrals -- bug?
- To: mathgroup at smc.vnet.net
- Subject: [mg67409] Re: Integrate with multiple integrals -- bug?
- From: Bill Rowe <readnewsciv at earthlink.net>
- Date: Thu, 22 Jun 2006 06:21:36 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
On 6/21/06 at 2:12 AM, ms_usenet at gmx.de (Martin Schoenecker) wrote:
>I am wondering where my or Mathematica's error in reasoning lies:
>In[1]:= Integrate[g[z], {x, 0, a}]
>Out[1]= a*g[z]
>ok, because the function g does not depend on x.
>In[2]:= Integrate[g[z], {z, 0, c}]
>Out[2]= Integrate[g[z], {z, 0, c}]
>ok, function g is not specified at the moment.
>In[3]:= Integrate[g[z], {z, 0, c}, {x, 0, a}]
>Out[3]= Integrate[a*g[z], {z, 0, c}]
>also ok. Now with the integration order reversed:
>In[4]:= Integrate[g[z], {x, 0, a}, {z, 0, c}]
>Out[4]= a*g[z]
>?? why this result ??
What version of Mathematica are you using. With
In[7]:=
$Version
Out[7]=
5.2 for Mac OS X (June 20, 2005)
I get
In[6]:=
Integrate[g[z],{z,0,c},{x,0,a}]==Integrate[g[z],{x,0,a},{z,0,c}]
Out[6]=
True
That is, I get the same output as your Out[3] above regardless of the order of integration.
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