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MathGroup Archive 2006

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Re: How to simplify exponents?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67421] Re: [mg67398] How to simplify exponents?
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Fri, 23 Jun 2006 04:31:34 -0400 (EDT)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

expr=2^(4(s-3)+1/2-s/2)

2^(4*(s - 3) - s/2 + 1/2)

Just use Simplify

expr//Simplify

2^((1/2)*(7*s - 23))

If you want to use a replacement rule, you need to use RuleDelayed (:>) and make the base a pattern as well

expr/.x_^n_:>x^Simplify[n]

2^((1/2)*(7*s - 23))

expr=A^(s+2(s/2+4))

A^(2*(s/2 + 4) + s)

expr//Simplify

A^(2*(s + 4))

expr/.x_^n_:>x^Simplify[n]

A^(2*(s + 4))


Bob Hanlon

---- "wandering.the.cosmos at gmail.com" <wandering.the.cosmos at gmail.com> wrote: 
> My computations in Mathematica yields some exponents that do not seem
> to get simplified automatically, e.g. 2^{4(s-3)+1/2-s/2}
> A^{s+2(s/2+4)}. I even tried to do x^n_ -> x^Simplify[n] but it doesn't
> work very well. Why is this so and how do I make sure my exponents are
> simplified?
> 
> Thanks!
> 


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