Re: How to simplify exponents?

*To*: mathgroup at smc.vnet.net*Subject*: [mg67421] Re: [mg67398] How to simplify exponents?*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Fri, 23 Jun 2006 04:31:34 -0400 (EDT)*Reply-to*: hanlonr at cox.net*Sender*: owner-wri-mathgroup at wolfram.com

expr=2^(4(s-3)+1/2-s/2) 2^(4*(s - 3) - s/2 + 1/2) Just use Simplify expr//Simplify 2^((1/2)*(7*s - 23)) If you want to use a replacement rule, you need to use RuleDelayed (:>) and make the base a pattern as well expr/.x_^n_:>x^Simplify[n] 2^((1/2)*(7*s - 23)) expr=A^(s+2(s/2+4)) A^(2*(s/2 + 4) + s) expr//Simplify A^(2*(s + 4)) expr/.x_^n_:>x^Simplify[n] A^(2*(s + 4)) Bob Hanlon ---- "wandering.the.cosmos at gmail.com" <wandering.the.cosmos at gmail.com> wrote: > My computations in Mathematica yields some exponents that do not seem > to get simplified automatically, e.g. 2^{4(s-3)+1/2-s/2} > A^{s+2(s/2+4)}. I even tried to do x^n_ -> x^Simplify[n] but it doesn't > work very well. Why is this so and how do I make sure my exponents are > simplified? > > Thanks! >