Solving an equation

• To: mathgroup at smc.vnet.net
• Subject: [mg67474] Solving an equation
• From: "masha" <mshunko at gmail.com>
• Date: Tue, 27 Jun 2006 03:14:48 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,

I need to solve an equation (below), however, when I use Solve, I get
an answer which I know cannot be correct (probably because Mathematica
uses Inverse). Is their a way to get around this problem and get a true

\!\(Assuming[\ A > 0\  && \ \
B\  > A\  && \ b > 1\  && \(P\^b\ Q\)\/a\  < \ \ B\  && \ \(P\^b\
Q\)\/a \
> A\  && \ P\^b\ Q = a\ B && \ a\  > \ 0\  && \ Co\  > \ 0\  && \ Cu\  >
0\  && tr\  > 0\  && \ tm > 0\  && \ Q > 0 && \ P >
0\  && T > 0, Solve[\(P\^\(\(-1\) - b\)\ \((\(-2\)\ a\ B\ P\^\(1
+ b\)\
Q + P\^\(2\ b\)\ \((P + b\ \((Co + Cu + P)\))\)\ Q\^2 - a\^2\ \((
A\^2\ b\ \((Co + T)\) + 2\ A\ \((\((\(-1\) + b)\)\ P - b\ Q\
T)\) + B\ \((\(-\((\(-2\) + B)\)\)\ P + b\ \((\(-2\)\ P +
B\ \((Cu +
P - T)\) + 2\ Q\ T)\))\))\))\)\)\/\(2\ a\ \((A - B)\)\) == 0,
P]]\)

Thank you,
Masha

```

• Prev by Date: Re: Listing ALL Options for a mathematica Function
• Next by Date: solving an equation with sums
• Previous by thread: Re: Getting Color *names* as strings?
• Next by thread: Re: Solving an equation