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MathGroup Archive 2006

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Solving an equation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67474] Solving an equation
  • From: "masha" <mshunko at gmail.com>
  • Date: Tue, 27 Jun 2006 03:14:48 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

I need to solve an equation (below), however, when I use Solve, I get
an answer which I know cannot be correct (probably because Mathematica
uses Inverse). Is their a way to get around this problem and get a true
answer?

\!\(Assuming[\ A > 0\  && \ \
    B\  > A\  && \ b > 1\  && \(P\^b\ Q\)\/a\  < \ \ B\  && \ \(P\^b\
Q\)\/a \
> A\  && \ P\^b\ Q = a\ B && \ a\  > \ 0\  && \ Co\  > \ 0\  && \ Cu\  >
      0\  && tr\  > 0\  && \ tm > 0\  && \ Q > 0 && \ P >
      0\  && T > 0, Solve[\(P\^\(\(-1\) - b\)\ \((\(-2\)\ a\ B\ P\^\(1
+ b\)\
      Q + P\^\(2\ b\)\ \((P + b\ \((Co + Cu + P)\))\)\ Q\^2 - a\^2\ \((
      A\^2\ b\ \((Co + T)\) + 2\ A\ \((\((\(-1\) + b)\)\ P - b\ Q\
      T)\) + B\ \((\(-\((\(-2\) + B)\)\)\ P + b\ \((\(-2\)\ P +
    B\ \((Cu +
      P - T)\) + 2\ Q\ T)\))\))\))\)\)\/\(2\ a\ \((A - B)\)\) == 0,
P]]\)

Thank you,
Masha


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