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Solving an equation
*To*: mathgroup at smc.vnet.net
*Subject*: [mg67474] Solving an equation
*From*: "masha" <mshunko at gmail.com>
*Date*: Tue, 27 Jun 2006 03:14:48 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
Hi,
I need to solve an equation (below), however, when I use Solve, I get
an answer which I know cannot be correct (probably because Mathematica
uses Inverse). Is their a way to get around this problem and get a true
answer?
\!\(Assuming[\ A > 0\ && \ \
B\ > A\ && \ b > 1\ && \(P\^b\ Q\)\/a\ < \ \ B\ && \ \(P\^b\
Q\)\/a \
> A\ && \ P\^b\ Q = a\ B && \ a\ > \ 0\ && \ Co\ > \ 0\ && \ Cu\ >
0\ && tr\ > 0\ && \ tm > 0\ && \ Q > 0 && \ P >
0\ && T > 0, Solve[\(P\^\(\(-1\) - b\)\ \((\(-2\)\ a\ B\ P\^\(1
+ b\)\
Q + P\^\(2\ b\)\ \((P + b\ \((Co + Cu + P)\))\)\ Q\^2 - a\^2\ \((
A\^2\ b\ \((Co + T)\) + 2\ A\ \((\((\(-1\) + b)\)\ P - b\ Q\
T)\) + B\ \((\(-\((\(-2\) + B)\)\)\ P + b\ \((\(-2\)\ P +
B\ \((Cu +
P - T)\) + 2\ Q\ T)\))\))\))\)\)\/\(2\ a\ \((A - B)\)\) == 0,
P]]\)
Thank you,
Masha
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