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Re: Pattern Matching for Exponentials

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67509] Re: Pattern Matching for Exponentials
  • From: bghiggins at ucdavis.edu
  • Date: Thu, 29 Jun 2006 00:09:13 -0400 (EDT)
  • References: <e7tejf$444$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Rick,

Try this

Exp[4 I t] /. Exp[Complex[0, n_]*t] -> Exp[Complex[0, n]*t]/(n^2 - 1)

(1/15)*E^(4*I*t)


Note that Sqrt[-1] is I not i

Cheers,

Brian


Rick Eller wrote:
> I am looking for a pattern-matching replacement rule which will
> transform exponential functions of the form exp(n i t) into
> (1/(n^2-1))exp(n i t) where i = sqrt[-1]. For example, exp(2 i t)
> should convert to (1/3)exp(2 i t). I've tried the following code without
> success :
>
> In:     Exp[2 i t]   /.  Exp[n_ i t] -> Exp[n i t]/(n^2-1)
>
> Out:  e^2 i t
>
> I would appreciate any suggestions as to how this code should be
> modified.
> 
> Thanks,
> 
> Rick Eller


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