Recognizing newline character in regular expressions

*To*: mathgroup at smc.vnet.net*Subject*: [mg67537] Recognizing newline character in regular expressions*From*: "D.C.Grady at gmail.com" <D.C.Grady at gmail.com>*Date*: Fri, 30 Jun 2006 04:14:09 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

I'm having trouble getting Mathematica to find the newline character in an input string. For example, dataString = " 0.0000 0.00 0.0000 1.00 2 0.0000 11.97 -131.00 1.00 1 0.0000 3.97 -134.00 1.00 1 0.1597 0.00 0.0251 1.00 2 0.1597 11.97 -130.00 1.00 1 0.1597 3.97 -134.00 1.00 1 1.4861 19.47 0.0000 1.00 -1 2.7083 0.00 0.3393 1.00 2 2.7083 11.97 -127.00 1.00 1"; I would like to write a function that would take a set of data values as a string in this sort of format and replace all the line breaks with some other string, say "*". So I tried In[53]:= StringReplace[dataString,RegularExpression["\n"]\[Rule]"*"] Out[53]= 0.0000 0.00 0.0000 1.00 2 0.0000 11.97 -131.00 1.00 1 \ 0.0000 3.97 -134.00 1.00 1 0.1597 0.00 0.0251 1.00 2 0.1597 \ 11.97 -130.00 1.00 1 0.1597 3.97 -134.00 1.00 1 1.4861 \ 19.47 0.0000 1.00 -1 2.7083 0.00 0.3393 1.00 2 2.7083 11.97 \ -127.00 1.00 1 which unfortunately don't to work. I've also tried matching RegularExpression["\\n"] EndOfLine StringExpression[\[NewLine]] none of which seem to work. The problem appears to be that Mathematica is automatically stripping newline characters out of the input string; this occurs even if I use the delayed evaluation assignment dataString:= ... Does anyone have any ideas? What's particularly aggravating is that if you look at the cell expression for the dataString cell, you can see that there are "\n" characters present in the string, and using this same approach works on the data with no problems when using a text processor that supports regular expressions.