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Re: Limit


Takamura wrote:
> Sinan Kapçak wrote:
>  
>>i want to find the value of the limit 
>>
>>1+(2/(3+(4/(5+(6/(7+... 
>>
>>how can i do that with Mathematica?
>>
> 
> Table[{i, 1 + N[FromContinuedFraction[Table[(j + 1)/j, {j, 2, i, 2}]], 
> 100]}, {i, 450, 500, 10}]
> Last[%][[2]]
> 

I'm sorry . This answers is wrong

to be so
g[n_] := FromContinuedFraction[Insert[a = 1; Table[a = j/a; (j + 1)/a, 
{j, 2, 2n, 2}], 1, 1]]
Table[{i, N[g[i], 100]}, {i, 55, 60}]
Last[%][[2]] - 1/(Sqrt[E] - 1)

0.x 10^-100

this is the same result which ealier send Daniel Lichtblau with function 
Fold

-- 
   takamura


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