[Date Index]
[Thread Index]
[Author Index]
Re: Factoring
*To*: mathgroup at smc.vnet.net
*Subject*: [mg65128] Re: [mg65069] Factoring
*From*: Murray Eisenberg <murray at math.umass.edu>
*Date*: Wed, 15 Mar 2006 06:29:03 -0500 (EST)
*Organization*: Mathematics & Statistics, Univ. of Mass./Amherst
*References*: <200603141059.FAA24051@smc.vnet.net>
*Reply-to*: murray at math.umass.edu
*Sender*: owner-wri-mathgroup at wolfram.com
In your first expression, I cannot see what the symbols are after the
"2*" inside the Sin function. To my eye it looks like it might be a
"hatted" I followed by a period, but that makes no sense.
If that is supposed to be an I also, then expression you gave is
real-valued (assuming that r is real):
4 I r^2 Sin[2 I] + I r^5 Sin[5 I
-4*r^2*Sinh[2] - r^5*Sinh[5]
If you prefer:
TrigToExp[4 I r^2 Sin[2 I] + I r^5 Sin[5 I]]
(2*r^2)/E^2 - 2*E^2*r^2 + r^5/(2*E^5) - (E^5*r^5)/2
In any event, for the last expression you gave, you could use:
4x I Sin[t] + 28x^3 I Cos[t]
I*(28*x^3*Cos[t] + 4*x*Sin[t])
(I've converted the output cells to InputForm.)
I realize that the above does not respond to your more general question.
Matt wrote:
> Hello Mathgroup,
> I'm sure that I've overlooked something obvious, but for the past two
> and a half hours, I've been trying to figure out how to use built-in
> Mathematica functions to just factor the imaginary number 'I' out of
> this:
>
> 4*I*r^2*Sin[2*Î¸] + I*r^5*Sin[5*Î¸]
>
> using Factor[] gives me I*r^2*(4*Sin[2*Î¸] + r^3*Sin[5*Î¸])
>
> using FactorTerms[] gives me I*(4*r^2*Sin[2*Î¸] + r^5*Sin[5*Î¸]) which
> is what I want, but as soon as I add in a common numerical factor, it
> also factors that out as well,
>
> e.g. 4*I*r^2*Sin[2*Î¸] + 8*I*r^5*Sin[5*Î¸]
>
> I finally just decided to divide the whole thing by 'I', and do some
> reconstruction of my expression, but I have the distinct feeling I've
> totally missed something very simple. As an additional example, what
> if I just wanted to extract 2*x*I out of the following:
>
> 4*x*I*Sin[t] + 28*x^3*I*Cos[t]
>
> how would I do that? In general, I'm looking for a function that says
> "Given an expression 'expr' and another expression 'sub' that is common
> to all additive terms of 'expr', give a result that is the product of
> 'sub' and the result of factoring 'sub' out of 'expr'".
>
> Thanks,
>
> Matt
>
>
--
Murray Eisenberg murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305
**References**:
**Factoring**
*From:* "Matt" <anonmous69@netscape.net>
Prev by Date:
**Re: Factoring**
Next by Date:
**Re: Sorting Rows of a Matrix**
Previous by thread:
**Re: Factoring**
Next by thread:
**Re: Factoring**
| |