Re: Conditions with Statistical Functions

• To: mathgroup at smc.vnet.net
• Subject: [mg66160] Re: [mg66091] Conditions with Statistical Functions
• From: Gregory Lypny <gregory.lypny at videotron.ca>
• Date: Tue, 2 May 2006 02:43:10 -0400 (EDT)
• References: <2252055.1146367664201.JavaMail.root@eastrmwml01.mgt.cox.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Thanks again, Bob.

Nice use of pure pure functions (Is that what they're called?).
Clearly, I have a long way to go in learning the syntax.  For
example, I never would have thought of using a question mark between
the x_List and VectorQ attribute because I'm still not up on what the
question mark means in general.  Bits and pieces are falling into
place though: I'm guessing that your use of the pound sign (#) in the
second statement refers to any vector, whereas in my limited use of
functions, such as Select, #[[1]] or #[[17]] would refer to the first
and seventeenth columns.

Greg

On Sat, Apr 29, 2006, at 11:27 PM, Bob Hanlon wrote:

> conditionalMean[x_List?VectorQ, cond_Function]:=
>     Mean[Select[x,cond]];
>
> conditionalMean[x_List, cond_Function]:=
>     conditionalMean[#,cond]&/@Transpose[x];
>
> m=Table[Random[Integer,200],{4},{3}]
>
> {{12, 138, 117}, {92, 13, 178}, {147, 131, 123}, {34, 177, 109}}
>
> Mean/@m
>
> {89, 283/3, 401/3, 320/3}
>
> Mean[m]
>
> {285/4, 459/4, 527/4}
>
> conditionalMean[#,(#>100)&]&/@m
>
> {255/2, 178, 401/3, 143}
>
> conditionalMean[m,(#>100)&]
>
> {147, 446/3, 527/4}
>
>
> Bob Hanlon
>
>
> ---- Gregory Lypny <gregory.lypny at videotron.ca> wrote:
>> Yes, thanks Bob.  But what about a matrix, where Mean operates
>> column-
>> wise?  Is there a compact statement where the mean will be calculated
>> over the values that exceed 100 in each column all in one shot?  What
>> I've been doing is looping Select across the columns using Do and
>> applying Mean on each pass.  I just thought there might be something
>> more efficient, if not more elegant.
>>
>> Regards,
>>
>> 	Greg
>>
>> On Sat, Apr 29, 2006, at 6:53 AM, Bob Hanlon wrote:
>>
>>> x={10,20,150,200,250};
>>>
>>> Mean[Select[x,#>100&]]
>>>
>>> 200
>>>
>>>
>>> Bob Hanlon
>>>
>>
>

```

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