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Re: Extract any diagonal from a square matrix...
*To*: mathgroup at smc.vnet.net
*Subject*: [mg66294] Re: [mg66279] Extract any diagonal from a square matrix...
*From*: Bob Hanlon <hanlonr at cox.net>
*Date*: Mon, 8 May 2006 00:46:22 -0400 (EDT)
*Reply-to*: hanlonr at cox.net
*Sender*: owner-wri-mathgroup at wolfram.com
Change the definition of d to be symmetric:
2 -- 2nd superdiagonal
1 -- 1st superdiagonal
0 -- main diagonal
-1 -- 1st subdiagonal
-2 -- 2nd subdiagonal
DiagonalT[a_List, d_Integer] :=
Module[{r=If[d>0,0,-d],
c=If[d>0,d,0]},
Table[a[[k+r,k+c]],
{k,1,Length[a]-Abs[d]}]]/;
Abs[d]<Length[a];
Bob Hanlon
---- hawkmoon269 <rson at new.rr.com> wrote:
> Trying to put a function together that extracts any one of the
> diagonals from a square matrix. Right now I have this --
>
> DiagonalT[a_List, d_Integer] :=
> Tr[Take[Which[Positive[d], a, Negative[d], Transpose[a]],
> {1, Length[a] - Abs[d] + 1}, {Abs[d], Length[a]}], List]
>
> This works, but I thought there might be something less cumbersome.
> Essentially, the function constructs a submatrix of the matrix so that
> the requested diagonal from the matrix becomes the main diagonal of the
> submatrix, which is then retrieved. D is the diagonal to retrieve,
> where d =
>
> 3 -- 2nd superdiagonal
> 2 -- 1st superdiagonal
> 1 -- main diagonal
> -2 -- 1st subdiagonal
> -3 -- 2nd subdiagonal
>
> etc...
>
> Some other things I've considered --
>
> ...rotating the elements of each row until column 1 becomes the
> requested diagonal;
> ...dropping elements from each row until the first or last element in
> each row becomes the next element in the requested diagonal;
> ...flattening the matrix and then using Range and Part to retrieve the
> requested diagonal.
>
> Any thoughts...?
>
> h
>
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