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MathGroup Archive 2006

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Re: building a list containing elements f(i,j)

  • To: mathgroup at smc.vnet.net
  • Subject: [mg71109] Re: [mg71045] building a list containing elements f(i,j)
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Wed, 8 Nov 2006 06:16:20 -0500 (EST)
  • Reply-to: hanlonr at cox.net

Table[f[i,j],{i,0,2},{j,0,3}]//Flatten

{f(0,0),f(0,1),f(0,2),f(0,3),f(1,0),f(1,1),f(1,2),f(1,3),f(2,0),f(2,1),f(2,
    2),f(2,3)}

Array[f,{3,4},{0,0}]//Flatten

{f(0,0),f(0,1),f(0,2),f(0,3),f(1,0),f(1,1),f(1,2),f(1,3),f(2,0),f(2,1),f(2,
    2),f(2,3)}

{Array[f,{3,4},{0,0},Sequence]}

{f(0,0),f(0,1),f(0,2),f(0,3),f(1,0),f(1,1),f(1,2),f(1,3),f(2,0),f(2,1),f(2,
    2),f(2,3)}

%==%%==%%%

True


Bob Hanlon

---- "xarnaudx at gmail.com" <xarnaudx at gmail.com> wrote: 
> 
> hi,
> i want to construct a list of the form:
> { f[1,1], ... f[n,m] }
> So the list contains elements of the form f[i,j] with i ranging from 0
> to n, and j from 0 to somebound[i].
> 
> What would be the most elegant way to this?
> thanks
> 

--

Bob Hanlon
hanlonr at cox.net



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