Re: Evaluating integral with varying upper limit?

*To*: mathgroup at smc.vnet.net*Subject*: [mg71074] Re: [mg71035] Evaluating integral with varying upper limit?*From*: Carl Woll <carlw at wolfram.com>*Date*: Wed, 8 Nov 2006 06:04:00 -0500 (EST)*References*: <200611060752.CAA08598@smc.vnet.net>

AES wrote: >Given a function f[x] which happens to be rather messy and not >analytically integrable, I want to evaluate the function > > g[y_] := NIntegrate[f[x], {x, ymin, y} ] > >with ymin fixed and ymin < y < Infinity. > >I suppose that FunctionInterpolate is the way to go here (???). > >But, are there tricks to tell FunctionInterpolate what I know in >advance, namely that f[x] is everywhere positive, and decreases toward >zero rapidly enough at large x that g[y] will approach a finite limiting >value as y -> Infinity? (which value I'd like to have FI obtain with >moderate accuracy -- meaning 3 or 4 significant digits, not 10 or 20) > >Thanks . . . > > I would recommend using NDSolve to invert the NIntegrate operation, although handling the range ymin<y<Infinity is problematic. For example: In[3]:= f[x_]:=BesselJ[2,x]Exp[-x] In[4]:= g[y_]:=NIntegrate[f[x],{x,1,y}] Then, using NDSolve we have: In[5]:= NDSolve[{h'[x] == f[x], h[1] == 0}, h, {x, 1, 100}] Out[5]= {{h -> InterpolatingFunction[{{1., 100.}}, <>]}} A few checks: g[10] h[10] /. %5[[1]] 0.102135 0.102135 g[100] h[100] /. %5[[1]] 0.102141 0.102141 g[Infinity] 0.102141 If you really need an InterpolationFunction whose range is ymin to Infinity, then you can try transforming variables, like y->1/y, but getting NDSolve to handle the point at Infinity (or 0 in transformed coordinates) becomes difficult. Carl Woll Wolfram Research

**Follow-Ups**:**Re: Re: Evaluating integral with varying upper limit?***From:*Carl Woll <carlw@wolfram.com>

**References**:**Evaluating integral with varying upper limit?***From:*AES <siegman@stanford.edu>