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MathGroup Archive 2006

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Re: Question about trig simplify

  • To: mathgroup at smc.vnet.net
  • Subject: [mg71180] Re: [mg71099] Question about trig simplify
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Thu, 9 Nov 2006 03:41:35 -0500 (EST)
  • Reply-to: hanlonr at cox.net

Use TrigReduce

2*Sin[a]*Cos[a]//TrigReduce

sin(2 a)

-2*Sin[a]*Cos[a]//TrigReduce

-sin(2 a)


Bob Hanlon

---- Robert Pigeon <robert.pigeon at videotron.ca> wrote: 
> 
> Hello all,
> 	Is this a bug?
> 
> 2*Sin[a]*Cos[a] // Simplify  gives Sin[2 a] as expected.
> 
> But
> 
> -2*Sin[a]*Cos[a] // Simplify  gives -2*Cos[a]*Sin[a]  ...... Why?
> If I do -2*(Sin[a]*Cos[a]) // Simplify I get the same answer.
> 
> This comes from the rotation matrix: r = {{Cos[a],Sin[a]},{-Sin[a],Cos[a]}}.
> Then I do: r.r // Simplify. That gives: {{Cos[2 a],Sin[2 a]},{-2 Cos[a]
> Sin[a],Cos[2 a]}}. It does not matter if I do a FullSimplify instead of
> Simplify.
> 
> After if I do r.r.r // Simplify. The answer is simplified correctly.
> 
> I am using Mathematica 5.2 on Windows XP Home.
> 
> Any idea?
> 
> Robert
> 
> Robert Pigeon
> TZ = -5 
> 


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