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Re: will someone explain the behavior of Unevaluated in this example?


sorry, that second one should be:

Block[{q = 5, f, g}, {Module[{f =
    Unevaluated[q], g}, g =
      Block[{Unevaluated}, First@f]; f === g], Unevaluated[q] === q}]

(and it still produces {False, False})

also, I have a similar expression in some code, and a TracePrint on it
contains this:

Unevaluated[names["1", "0"]] === names["1", "0"]

with the _next line_ saying False

(even though Unevaluated and SameQ aren't Blocked and names isn't
Blocked, but doesn't have a value) (afaik)

On 11/18/06, Chris Chiasson <chris at chiasson.name> wrote:
> Block[{q = 5, f, g}, {Module[{f =
>     Unevaluated[q], g}, g = Evaluate@f; f === g], Unevaluated[q] === q}]
>
> gives {True,False}, which is unexpected (by myself)
>
> Block[{q = 5, f, g}, {Module[{f = Unevaluated[q], g},
>     g = Block[{Unevaluated}, f]; f === g], Unevaluated[q] === q}]
>
> gives {False,False}, as expected
>
> --
> http://chris.chiasson.name/
>


-- 
http://chris.chiasson.name/


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