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MathGroup Archive 2006

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Re: AGAIN Nested while loop!!!

  • To: mathgroup at smc.vnet.net
  • Subject: [mg71646] Re: AGAIN Nested while loop!!!
  • From: dh <dh at metrohm.ch>
  • Date: Sat, 25 Nov 2006 05:37:35 -0500 (EST)
  • References: <ek63rd$907$1@smc.vnet.net>

Hi,
you got the syntax of "If" wrong. This works:
result={};
For[i=1,i<=6,i++,
     For[j=i+1,j<=6,j++,
       If[lst[[i]]==lst[[j]],result={i,j};Break[]]]
     ];
result
Concerning the While loop, the logic is wrong. This works:
result = {};
i = 0;
While[++i <= 6,
     j = i;
     While[++j <= 6, If[lst[[i]] == lst[[j]], result = {i, j}; Break[]]
       ]
     ];
result
Daniel

mumat wrote:
> I have a list of numbers
> 
> lst = Table[Random[Integer, {i, 50}], {i, 6}]
> 
> I want to write a program that if There are two numbers x, y in A where
> 
> 
> Mod[x^2+y^2, 5]==0  reuturn False and the pair {x,y}, otherwise True!
> 
> 
> For[i = 0, i < 6, For[j = i, j < 6,
>   If[Mod[lst[[i]]^2 + lst[[j]]^2, 3] == 0,
> Return[False,{i,j}]];Break[], j++], i++]
> 
> While loop and nested while loops accept only one counter "i".
> 
> i=1;j=2;
> 
> While[i<6 && While[j<6 &&
> Mod[lst[[i]]^2+lst[[j]]^2,7]=!=0,j++];i++];{i,j}
> 
> {2,6}
> 
> 
> Would be great if you could help me with this!!
> 
> 
> Regards,
> 
> chekad
> 


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