Re: Update on Weinberg-Sallam model in super symmetry as E8xE8-> energy of split
- To: mathgroup at smc.vnet.net
- Subject: [mg70336] Re: Update on Weinberg-Sallam model in super symmetry as E8xE8-> energy of split
- From: Roger Bagula <rlbagula at sbcglobal.net>
- Date: Fri, 13 Oct 2006 01:30:44 -0400 (EDT)
- References: <egl44b$53a$1@smc.vnet.net>
Roger Bagula wrote:
>I spent yesterday learning about super symmetric Higgs symmetry breaking
>theory.
>
>
>
>
>
Sorry about the spelling in the title, ha, ha...
The bonding model for the "between " super symmetry model that comes to
mind is the trigonal prism:
A120656 6by6 trigonal prism bonding graph matrix Markov:
this molecular structure is the major symmetry between the tetrahedron
and cube:
characteristic polynomial:12 x^2 - 4 x^3 - 9 x^4 + x^6.
The problem with that is it puts the energy for the H+,H- state between
the Z0 and W+,W-.
{-2,-2,0,0,1,3}
An alternative is the octahedral:
A120470 6X6 Matrix Markov of the octahedral bonding graph.
{-2., -2., 0., 0., 0., 4.}
That puts energy of Z0->H+,H-
and ?
H0=3*MW~273.6 gev
Which is much higher than I would expect.
My idea was that they would be symmetrical like:
{-A,-B,-B,B,B,A}
So that
MH0=2*MZ0~ 182.3 gev
MH(+/-)=2*MW~160.6 gev
I have got a 6by6 bonding model that gives that as a cyclic bonding (
like benzene) :
{-2., -1., -1., 1., 1., 2.}->{Z0,W+,W-,H+,H-,H0}
A120462 6 X 6 Matrix Markov based on hexagon / benzene
chemical bonding
type Markov with characteristic polynomial : x^6-6*x^4+9*x^2-4.
Mathematica:
M = {{0, 1, 1, 1, 0, 0},
{1, 0, 1, 0, 1, 0},
{1, 1, 0, 0, 0, 1},
{1, 0, 0, 0, 1, 1},
{0, 1, 0, 1, 0, 1},
{0, 0, 1, 1, 1, 0}}
v[1] = {0, 1, 1, 2, 3, 5}
v[n_] := v[n] = M.v[n - 1]
a = Table[Floor[v[n][[1]]], {n, 1, 50}]
Det[M - x*IdentityMatrix[6]]
Factor[%]
aaa = Table[x /. NSolve[Det[M - x*IdentityMatrix[6]] == 0, x][[
n]], {n, 1, 6}]
Abs[aaa]
a1 = Table[N[a[[n]]/a[[n - 1]]], {n, 7, 50}]
I will not imply mine is better than nature,
so each of these possibility is about equally likely.