Re: Re: GraphPlot

*To*: mathgroup at smc.vnet.net*Subject*: [mg70824] Re: [mg70809] Re: [mg70775] GraphPlot*From*: Bruce Colletti <vze269bv at verizon.net>*Date*: Sat, 28 Oct 2006 23:37:56 -0400 (EDT)

Carl In v5.2, why does: GraphPlot[{...}, VertexStyleFunction -> (Text[#, #] &) fail when {0,-1} is the Text offset? GraphPlot[{1 -> 2, 2 -> 3, 3 -> 1, 3 -> 4, 5 -> 6, 6 -> 5}, VertexStyleFunction -> (Text[#, #,{0,-1}] &) Thankx. Bruce ===================== From: Carl Woll <carlw at wolfram.com> To: mathgroup at smc.vnet.net Subject: [mg70824] [mg70809] Re: [mg70775] GraphPlot Matt Curcio wrote: > Carl, > Thanks for your reply. Sorry I was unclear, let me try to > explain better with a simpler example. When you run the code: > > << DiscreteMath`GraphPlot`; > GraphPlot[{1 -> 2, 2 -> 3, 3 -> 1, 3 -> 4, 5 -> 6, 6 -> 5}, > VertexStyleFunction -> (Text[#, #] &) > > > You see two graphs with the vertices labeled. The rightmost graph is > composed of the components {5->6, 6->5}. But the only way I know > that is because I've labeled the vertices and my dataset above is so > small. What I would like is a function that does the following: > > MagicalGraphCoordinatesFunction[ {1 -> 2, 2 -> 3, 3 -> 1, 3 -> 4, 5 - > > 6, 6 -> 5} ]; > > which returns: > {{1 -> 2, 2 -> 3, 3 -> 1, 3 -> 4}, {5 -> 6, 6 -> 5}} > > i.e. A list with the elements of the two directed graphs in my data. > I am essentially using GraphPlot to discover how many directed graph > clusters are in my data. Its great to visualize them, but I would > really like to know which elements make up the subgraphs. > > Thanks again, > Matt Did you try the code I gave in my last post? Trying it out on this example, we have: gr={1 -> 2, 2 -> 3, 3 -> 1, 3 -> 4, 5 -> 6, 6 -> 5} In[9]:= StrongComponents[Join[gr, Reverse /@ gr]] Out[9]= {{1, 2, 3, 4}, {5, 6}} This isn't quite what you asked for, but it's close. Carl Woll Wolfram Research > > > > On Oct 27, 2006, at 5:13 AM, Carl Woll wrote: > >> Matt Curcio wrote: >> >>> Hi, >>> I have a question about extracting data from the internals of >>> GraphPlot. For example, the following code plots multiple >>> subplots of disconnected clusters. >>> >>> << DiscreteMath`GraphPlot` >>> n = 129; >>> d = Table[i -> Mod[i^2, n], {i, 0, n - 1}]; >>> GraphPlot[d]; >>> >>> However, I would like to know the subsets that are being plotted. >>> I know you can plot the vertex labels on the chart, but my dataset >>> is ~50,000 connected vertices and GraphPlot outputs ~100 clusters, >>> so vertex labeling is unrealistic. It would be very interesting >>> to know which vertices GraphPlot has associated. There maybe a >>> way to do this using some functions from "Combninatorica" but I >>> have not been able to find them. Can anyone help? >>> >>> Thanks, >>> Matt >>> >> I'm not clear on what you want, but have you tried StrongComponents >> from the GraphPlot package? This function will give you a list of >> the vertices in each disconnected cluster (assuming the graph is >> undirected). In your example, we would convert d to an undirected >> graph and then use StrongComponents: >> >> comps = StrongComponents[ Join[d, Reverse/@d] ]; >> >> In[30]:= >> Length[comps] >> Out[30]= >> 14 >> >> Carl Woll >

**Re: DisplayTogether & PlotLegend incompatibility**

**Why all the if's the answer (revised!!!)**

**Re: GraphPlot**

**Re: Re: GraphPlot**