RE: Mapping Functions That Take More Than One Argument
- To: mathgroup at smc.vnet.net
- Subject: [mg69894] RE: [mg69864] Mapping Functions That Take More Than One Argument
- From: "David Park" <djmp at earthlink.net>
- Date: Wed, 27 Sep 2006 06:03:46 -0400 (EDT)
Gregory,
To map a function with more than one argument over a list, use a pure
function with the other arguments filled in.
testlist = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
Map[Drop[#, 1] &, testlist]
{{2, 3}, {5, 6}, {8, 9}}
Or
Drop[#, 1] & /@ testlist
{{2, 3}, {5, 6}, {8, 9}}
Suppose you want to map over two lists, one for each argument? Suppose you
want to drop 1 argument in the first list, 2 arguments in the second list,
and the last argument in the third list. Do it with a pure function and
MapThread.
MapThread[Drop[#1, #2] &, {testlist, {1, 2, -1}}]
{{2, 3}, {6}, {7, 8}}
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
From: Gregory Lypny [mailto:gregory.lypny at videotron.ca]
To: mathgroup at smc.vnet.net
Hello everyone,
How can I map a functions onto sub-lists when the function takes more
than one argument. I can't seem to stumble upon the right syntax.
Here's a list of three sub-lists.
{{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}
I want to drop the first element of each sub-list, that is, 1 from
the first, 4 from the second, and 7 from the third.
Drop[{{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}, 1]
gives me
{{4, 5, 6}, {7, 8, 9}},
which is what I expected (I'm learning) but not what I want. So, how
do I apply Drop to each sub-list?
Regards,
Gregory