plot questions
- To: mathgroup at smc.vnet.net
- Subject: [mg69980] plot questions
- From: dimmechan at yahoo.com
- Date: Thu, 28 Sep 2006 06:17:41 -0400 (EDT)
In connection with a recent post of mine (http://groups.google.gr/group/comp.soft-sys.math.mathematica/browse_thread/thread/9836d5644ef5b0a1/990d325c2340ea2a?hl=el#990d325c2340ea2a) I have two questions The following plots give some insight about the real and imaginary part of a given function, e.g. cos(x) ContourPlot[Evaluate[Re[Cos[z] /. z -> x + I*y]], {x, -Pi, Pi}, {y, -Pi, Pi}, Contours -> 30, PlotPoints -> 30, ContourShading -> None, Frame -> {True, True, False, False}, FrameLabel -> {"\nRe[z]", "Im[z]\n"}] ContourPlot[Evaluate[Im[Cos[z] /. z -> x + I*y]], {x, -Pi, Pi}, {y, -Pi, Pi}, Contours -> 30, PlotPoints -> 30, ContourShading -> None, Frame -> {True, True, False, False}, FrameLabel -> {"\nRe[z]", "Im[z]\n"}] Is is another way to get a similar plot without using ContourPlot? Consider now the following function f[z_] := Cos[z] - z ref[x_, y_] := Re[f[z] /. z -> x + I*y] imf[x_, y_] := Im[f[z] /. z -> x + I*y] Here are two parametric plots ParametricPlot[{ref[x, y], imf[x, y]} /. y -> Pi, {x, -Pi, Pi}] ParametricPlot[{ref[x, y], imf[x, y]} /. x -> Pi/3, {y, -Pi, Pi}] In the previous plot we keep one variable fixed. What I want (if this is possible) is a plot in which in one axis will be the real part of f[z] and in the other axis the imaginary but both x=[z] and y=Im[z] to vary on some range. Thanks