Finding unknown parameters using Mathematica
- To: mathgroup at smc.vnet.net
- Subject: [mg74722] Finding unknown parameters using Mathematica
- From: "Shafiq Ahmad" <shafiq.ahmad at rmit.edu.au>
- Date: Mon, 2 Apr 2007 06:55:58 -0400 (EDT)
Dear group members, I'm very new to mathematica and trying to solve a set of non-linear system = of equations to find the unknown parameters for a bivariate distribution. = I've 5 unknown parameters (i.e. b1,b2,r1,r2,p) and 5 set of equations. I = tried to get the general solution , but could not. I don't know how to = solve these nonlinear equations to get the unknown parameters. And also = not aware how to give initial value in the solve function or any other = function (e.g all parameters b1,b2,r1,r2,p if I give initial boundary = value =1). In the below codes, x1 and x2 are 2 variables (e.g. data from 2 quality = characteristics; stress and strain etc. etc.) Any comments / suggestions how to solve these equation for b1,b2,r1,r2,p = where as putting intial value for all these unknown parameters =1 Ahmad S. =================== n=4 x1={1,2,3,4} x2={1.7,3.8,4.9,4.6} 4 {1,2,3,4} {1.7,3.8,4.9,4.6} \!\(\* RowBox[{ RowBox[{ StyleBox["L", FontSize->10], StyleBox["=", FontSize->14], StyleBox[\(n*Log[p] + n*Log[p + 1] + n* Log[b1] + n*Log[r1] + n*Log[b2] + n*Log[r2] + \((b1 - 1)\) = \(=E2=88=91\+\(j = 1\)\%n Log[x1[\([ j]\)]]\) + \((b2 - 1)\) \(=E2=88=91\+\(j = 1\)\%n Log[ x2[\([j]\)]]\) - \((p + 2)\) \(=E2=88=91\+\(j = 1\)\%n Log[1 + r1*\((x1[\([j]\)]^b1)\) + r2*\((x2[\([j]\)]^b2)\)]\)\), FontSize->14, FontColor->RGBColor[1, 0, 0]]}], "\[IndentingNewLine]", StyleBox[" ", FontSize->18]}]\) \!\(4.980920826406141`\ \((\(-1\) + b2)\) + \((\(-1\) + b1)\)\ \(( Log[2] + Log[3] + Log[ 4])\) + 4\ Log[b1] + 4\ Log[b2] + 4\ Log[ p] + 4\ Log[1 + p] + 4\ Log[r1] + 4\ Log[r2] - \((2 + p)\)\ \(( Log[1 + r1 + 1.7`\^b2\ r2] + Log[1 + 2\^b1\ r1 + 3.8`\^b2\ r2] + Log[1 + 4\^b1\ r1 + 4.6`\^b2\ r2] + Log[1 + 3\^b1\ r1 + = 4.9`\^b2\ r2])\)\) Eqn1=D[L,r1]\[Equal]0 \!\(4\/r1 - \((2 + p)\)\ \((1\/\(1 + r1 + 1.7`\^b2\ r2\) + 2\^b1\/\(1 + 2\^b1\ r1 + 3.8`\^b2\ r2\) + 4\^b1\/\(1 + 4\^b1\ r1 + 4.6`\^b2\ r2\) + 3\^b1\/\(1 + 3\^b1\ r1 + = 4.9`\^b2\ \ r2\))\) \[Equal] 0\) Eqn2=D[L,r2]\[Equal]0 \!\(4\/r2 - \((2 + p)\)\ \((1.7`\^b2\/\(1 + r1 + 1.7`\^b2\ r2\) + 3.8`\^b2\/\(1 + 2\^b1\ r1 + 3.8`\^b2\ r2\) = + \ 4.6`\^b2\/\(1 + 4\^b1\ r1 + 4.6`\^b2\ r2\) + 4.9`\^b2\/\(1 + 3\^b1\ r1 + = 4.9`\^b2\ \ r2\))\) \[Equal] 0\) Eqn3=D[L,b1]\[Equal]0 \!\(4\/b1 + Log[2] + Log[3] + Log[4] - \(( 2 + p)\)\ \((\(2\^b1\ r1\ Log[2]\)\/\(1 + 2\^b1\ r1 + 3.8`\^b2\ r2\) + \(3\^b1\ r1\ Log[3]\)\/\(1 + 3\^b1\ r1 + 4.9`\^b2\ r2\) + = \ \(4\^b1\ r1\ Log[4]\)\/\(1 + 4\^b1\ r1 + 4.6`\^b2\ r2\))\) \[Equal] 0\) Eqn4=D[L,b2]\[Equal]0 \!\(\(\(4.980920826406141`\)\(\[InvisibleSpace]\)\) + 4\/b2 - \((2 + p)\)\ \((\(0.5306282510621704`\ 1.7`\^b2\ r2\)\/\(1 = + r1 + 1.7`\^b2\ r2\) + \(1.33500106673234`\ 3.8`\^b2\ r2\)\/\(1 + 2\^b1\ r1 + = \ 3.8`\^b2\ r2\) + \(1.5260563034950492`\ 4.6`\^b2\ r2\)\/\(1 + 4\^b1\ r1 + = \ 4.6`\^b2\ r2\) + \(1.589235205116581`\ 4.9`\^b2\ r2\)\/\(1 + 3\^b1\ r1 + = 4.9`\ \^b2\ r2\))\) \[Equal] 0\) Eqn5=D[L,p]\[Equal]0 \!\(4\/p + 4\/\(1 + p\) - Log[1 + r1 + 1.7`\^b2\ r2] - Log[1 + 2\^b1\ r1 + 3.8`\^b2\ r2] - Log[1 + 4\^b1\ r1 + 4.6`\^b2\ r2] - Log[1 + 3\^b1\ r1 + 4.9`\^b2\ r2] \[Equal] 0\) Solve[{Eqn1,Eqn2,Eqn3,Eqn4,Eqn5},{r1,r2,b1,b2,p}]
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