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MathGroup Archive 2007

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Re: Solving periodic functions

  • To: mathgroup at
  • Subject: [mg75000] Re: [mg74935] Solving periodic functions
  • From: Jmbatista at
  • Date: Fri, 13 Apr 2007 02:17:18 -0400 (EDT)

When dealing with transcendental functions, you should be able  to obtain all 
roots using the command "Reduce" instead of "Solve".   Therefore, given that 
0 < x <= 2 Pi, try the following  command:
            Reduce[6*Cos[x]  - 5*Cos[x] == 0, x]
Hope this helps,
J. Batista
In a message dated 4/12/2007 5:08:56 A.M. Eastern Daylight Time,  
w3bdevilREMOVE at writes:

This is  probably totally elementary, but I'm stumped nonetheless.

Anyway, in  Mathematica, how do I solve an equation with multiple periodic 
functions  within a given function domain bound?

i.e. How would I find all values  of x given 6Cos[x]-5Cos[x] = 0 where 
0<x<=2Pi ?



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