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Re: Solving periodic functions
*To*: mathgroup at smc.vnet.net
*Subject*: [mg75000] Re: [mg74935] Solving periodic functions
*From*: Jmbatista at aol.com
*Date*: Fri, 13 Apr 2007 02:17:18 -0400 (EDT)
When dealing with transcendental functions, you should be able to obtain all
roots using the command "Reduce" instead of "Solve". Therefore, given that
0 < x <= 2 Pi, try the following command:
Reduce[6*Cos[x] - 5*Cos[x] == 0, x]
Hope this helps,
J. Batista
______________
In a message dated 4/12/2007 5:08:56 A.M. Eastern Daylight Time,
w3bdevilREMOVE at THISw3bdevil.com writes:
This is probably totally elementary, but I'm stumped nonetheless.
Anyway, in Mathematica, how do I solve an equation with multiple periodic
functions within a given function domain bound?
i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where
0<x<=2Pi ?
thanks
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