Re: Solving periodic functions

*To*: mathgroup at smc.vnet.net*Subject*: [mg75000] Re: [mg74935] Solving periodic functions*From*: Jmbatista at aol.com*Date*: Fri, 13 Apr 2007 02:17:18 -0400 (EDT)

When dealing with transcendental functions, you should be able to obtain all roots using the command "Reduce" instead of "Solve". Therefore, given that 0 < x <= 2 Pi, try the following command: Reduce[6*Cos[x] - 5*Cos[x] == 0, x] Hope this helps, J. Batista ______________ In a message dated 4/12/2007 5:08:56 A.M. Eastern Daylight Time, w3bdevilREMOVE at THISw3bdevil.com writes: This is probably totally elementary, but I'm stumped nonetheless. Anyway, in Mathematica, how do I solve an equation with multiple periodic functions within a given function domain bound? i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where 0<x<=2Pi ? thanks