Re: Solving periodic functions

• To: mathgroup at smc.vnet.net
• Subject: [mg75000] Re: [mg74935] Solving periodic functions
• From: Jmbatista at aol.com
• Date: Fri, 13 Apr 2007 02:17:18 -0400 (EDT)

```
When dealing with transcendental functions, you should be able  to obtain all
roots using the command "Reduce" instead of "Solve".   Therefore, given that
0 < x <= 2 Pi, try the following  command:

Reduce[6*Cos[x]  - 5*Cos[x] == 0, x]

Hope this helps,
J. Batista
______________
In a message dated 4/12/2007 5:08:56 A.M. Eastern Daylight Time,
w3bdevilREMOVE at THISw3bdevil.com writes:

This is  probably totally elementary, but I'm stumped nonetheless.

Anyway, in  Mathematica, how do I solve an equation with multiple periodic
functions  within a given function domain bound?

i.e. How would I find all values  of x given 6Cos[x]-5Cos[x] = 0 where
0<x<=2Pi ?

thanks

```

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