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MathGroup Archive 2007

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Re: ImplicitPlot errors

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75128] Re: [mg75066] ImplicitPlot errors
  • From: Jmbatista at aol.com
  • Date: Wed, 18 Apr 2007 04:58:16 -0400 (EDT)

 
David, to make plots of implicitly-defined functions, you  first need to load 
the "ImplicitPlot.m" standard package using the following  command:
        <<"Graphics`ImplicitPlot`";
Best regards,
J. Batista
_________________
In a message dated 4/16/2007 4:45:50 A.M. Eastern Daylight Time,  
w3bdevilREMOVE at THISw3bdevil.com writes:

Hi,

I've been trying to get ImplicitPlot to plot an implicit  function (naturally 
;) ), but it throws errors to cryptic for me, even  when copying and pasting 
from the Mathematica function  reference.

In[40]:= ImplicitPlot[{x^2 + x*y + y^2 == 7, y ==  2*Sqrt[7/3]}, {x, -5, 5}]

ImplicitPlot::var :

Equation x^2+x  
Function[x,x^2+2xy-3y^2-16]+Function[x,x^2+2xy-3<<1>>-16]^2==7  does not have 
a single variable other than x

ImplicitPlot::var  :

Equation Function[x,x^2+2xy-3y^2-16]==2Sqrt(7/3) does not have a  single 
variable other than x

Out[40]:=\!\(ImplicitPlot[{x\^2 + x\  Function[x, x\^2 + 2\
xy - 3\ y\^2 - 16]  + Function[
x, x\^2 + 2\  xy - 3\ y\^2 - 16]\^2 == 7, Function[x, x\^2 + 2\
xy - 3\ y\^2 - 16] == 2\ \@\(7\/3\), x == 2\  \@\(7\/3\)}, {x, 
\
\(-5\), 5}, {Function[x, x\^2 + 2\ xy - 3\ y\^2 -  16], \(-5\), 5}]\)



What am I doing wrong? Even  ImplicitPlot[x+y==2,{x,-4,4}]  fails.

Thanks




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