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Re: ImplicitPlot errors
*To*: mathgroup at smc.vnet.net
*Subject*: [mg75128] Re: [mg75066] ImplicitPlot errors
*From*: Jmbatista at aol.com
*Date*: Wed, 18 Apr 2007 04:58:16 -0400 (EDT)
David, to make plots of implicitly-defined functions, you first need to load
the "ImplicitPlot.m" standard package using the following command:
<<"Graphics`ImplicitPlot`";
Best regards,
J. Batista
_________________
In a message dated 4/16/2007 4:45:50 A.M. Eastern Daylight Time,
w3bdevilREMOVE at THISw3bdevil.com writes:
Hi,
I've been trying to get ImplicitPlot to plot an implicit function (naturally
;) ), but it throws errors to cryptic for me, even when copying and pasting
from the Mathematica function reference.
In[40]:= ImplicitPlot[{x^2 + x*y + y^2 == 7, y == 2*Sqrt[7/3]}, {x, -5, 5}]
ImplicitPlot::var :
Equation x^2+x
Function[x,x^2+2xy-3y^2-16]+Function[x,x^2+2xy-3<<1>>-16]^2==7 does not have
a single variable other than x
ImplicitPlot::var :
Equation Function[x,x^2+2xy-3y^2-16]==2Sqrt(7/3) does not have a single
variable other than x
Out[40]:=\!\(ImplicitPlot[{x\^2 + x\ Function[x, x\^2 + 2\
xy - 3\ y\^2 - 16] + Function[
x, x\^2 + 2\ xy - 3\ y\^2 - 16]\^2 == 7, Function[x, x\^2 + 2\
xy - 3\ y\^2 - 16] == 2\ \@\(7\/3\), x == 2\ \@\(7\/3\)}, {x,
\
\(-5\), 5}, {Function[x, x\^2 + 2\ xy - 3\ y\^2 - 16], \(-5\), 5}]\)
What am I doing wrong? Even ImplicitPlot[x+y==2,{x,-4,4}] fails.
Thanks
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