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Block vs. ReplaceAll
*To*: mathgroup at smc.vnet.net
*Subject*: [mg79907] Block vs. ReplaceAll
*From*: Neil Stewart <neil.stewart at warwick.ac.uk>
*Date*: Wed, 8 Aug 2007 04:57:16 -0400 (EDT)
*Reply-to*: Neil Stewart <neil.stewart at warwick.ac.uk>
Take a function f of some global variables and a function g that depends on
f.
f := a^2 + b^2 (* f is a function of a and b, a and b are global variables *)
g := Count[Table[f, {10}], 0] (* g in turn depends on f *)
Solutions can be found for a and b that minimize f.
solution = NMinimize[{f, a > 0 && b > 0}, {a, b}]
{0., {a -> 0., b -> 0.}}
But how is it best to use the solution?
Block[{a = 0, b = 0}, f] (* Fast *)
0
or
f /. Last[solution] (* Slow *)
0
For this trivial example obviously both are fast, but when f is non-trivial,
Block[] is much faster.
Further for g, only Block[] works as I intend (counting the number of times
ten calls to f evaluate 0):
Block[{a = 0, b = 0}, g] (* Fast and works as I intend *)
10
g /. Last[solution] (* Slow, and doesn't count the number of times f is zero as I intended *)
I understand why this happens: Count[] counts the fs in the table in symbolic
form, before a and b are replaced and f is evaluated at 0.
My question is, how is it best to take "solution" - which is a list of
replace rules - and use it in a Block[] statement - which requires a list of
assignments? I need the speed that Block[] gives by making replacements before
f is evaluated. I'm keen to keep the simplicity of having model parametes as
global variables to avoid having to pass model parameters explicitly to
model functions as this is messy with a non-trivial model.
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