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MathGroup Archive 2007

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Integrate with PrincipalValue->True

  • To: mathgroup at smc.vnet.net
  • Subject: [mg79924] Integrate with PrincipalValue->True
  • From: chuck009 <dmilioto at comcast.com>
  • Date: Thu, 9 Aug 2007 05:12:09 -0400 (EDT)

Can someone explain to me how Integrate calculates the following improper integral?

In[42]:= $Version
Integrate[Sqrt[x]/(1 - x^2), {x, 0, a}, 
   PrincipalValue -> True, Assumptions -> 
     a > 1]

Out[42]= "6.0 for Microsoft Windows (32-bit) (June 19, 2007)"

Out[43]= ArcCoth[Sqrt[a]] - ArcTan[Sqrt[a]]

Thanks,
Charles


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