Fourier transform : failure with hyperbolic secant and log argument
- To: mathgroup at smc.vnet.net
- Subject: [mg79926] Fourier transform : failure with hyperbolic secant and log argument
- From: lagaffe <spambox at neuf.fr>
- Date: Thu, 9 Aug 2007 05:13:12 -0400 (EDT)
Hi all, Does someone know why Mathematica succeeds in findind the fourier transform of Sech[x*a] but not of Sech[x*Log], and why does it return a result in terms of gamma functions with Sech[x*Log[2.0]] ?? I know this is not really an issue since I can replace Log by the symbol a, but it worries me about mathematica's reliability. Thanks.