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Re: Simplifying the exponents


Hi,

Exp[I (q1 y1 + q2 y2 + q3 y3) - I (qp1 y1 + qp2 y2 + qp3 y3)] /.
  Exp[a_] :> Exp[Collect[a, {y1, y2, y3}]]

will do the first, the second will not work easyly because Mathematica
will always simplify Exp[a]*Exp[b] to Exp[a+b]

Regards
    Jens

Jung-Tsung Shen wrote:
> Hello, I would like to ask a question which I haven't been able to
> find a solution that does not need human intervening.
> 
> I would like to simplify the following expression
> 
> Exp[I (q1 y1 + q2 y2 + q3 y3) - I (qp1 y1 + qp2 y2 + qp3 y3)]
> 
> according to y1, y2, and y3 so it would look like
> 
> Exp[I (q1-qp1) y1+ I (q2-qp2) y2 + I (q3-qp3) y3], or
> 
> Exp[I (q1-qp1) y1] * Exp[I (q2-qp2) y2] * Exp[I (q3-qp3) y3]
> 
> How could I achieve this in an efficient way?
> 
> Thanks.
> 
> JT
> 


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