       Re: Simplifying the exponents

• To: mathgroup at smc.vnet.net
• Subject: [mg80017] Re: Simplifying the exponents
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Fri, 10 Aug 2007 06:43:07 -0400 (EDT)
• Organization: Uni Leipzig
• References: <f9gv3l\$b5e\$1@smc.vnet.net>

```Hi,

Exp[I (q1 y1 + q2 y2 + q3 y3) - I (qp1 y1 + qp2 y2 + qp3 y3)] /.
Exp[a_] :> Exp[Collect[a, {y1, y2, y3}]]

will do the first, the second will not work easyly because Mathematica
will always simplify Exp[a]*Exp[b] to Exp[a+b]

Regards
Jens

Jung-Tsung Shen wrote:
> Hello, I would like to ask a question which I haven't been able to
> find a solution that does not need human intervening.
>
> I would like to simplify the following expression
>
> Exp[I (q1 y1 + q2 y2 + q3 y3) - I (qp1 y1 + qp2 y2 + qp3 y3)]
>
> according to y1, y2, and y3 so it would look like
>
> Exp[I (q1-qp1) y1+ I (q2-qp2) y2 + I (q3-qp3) y3], or
>
> Exp[I (q1-qp1) y1] * Exp[I (q2-qp2) y2] * Exp[I (q3-qp3) y3]
>
> How could I achieve this in an efficient way?
>
> Thanks.
>
> JT
>

```

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