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MathGroup Archive 2007

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FindRoot and Interpolating function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg80273] FindRoot and Interpolating function
  • From: vmany <veeramany.arun at gmail.com>
  • Date: Thu, 16 Aug 2007 04:48:10 -0400 (EDT)

FindRoot[S[a[1]] == 0.0018, {a[1], 50}]

where S[a[1]] below contains an interpolating function.

\!\(\*
  RowBox[{\(0.00001799999999999999`\ \[ExponentialE]\^\(1\/4\ \((50 -
a[1])\)\
\)\), "+",
    FractionBox[
      RowBox[{"0.09999999999999998`", " ", \(\[ExponentialE]\^\(\
(-0.25`\)\ a[
    1.`]\)\), " ", \((\(-50.`\) + a[1])\), " ",
        RowBox[{"(",
          RowBox[{\(\(1216.24812344918`\)\(\[InvisibleSpace]\)\),
"+",
            RowBox[{\(\[ExponentialE]\^\(0.25`\ a[1.`]\)\), " ",
              RowBox[{
                TagBox[\(InterpolatingFunction[{{0.`, 89.`}}, "<>"]\),
                  False,
                  Editable->False],
          "[", \(\(\(0.`\)\(\[InvisibleSpace]\)\) + a[1.`]\),
             "]"}]}]}], ")"}]}], \(\(-50.`\) + a[1.`]\)]}]\)

FindRoot gives the following error:
FindRoot::nlnum: The function value ...is not a list of numbers with
dimensions {1} at {a[1]} = {55.}

How do I deal with this?

Many thanks
Arun



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