Re: Partition a list into sublists of unequal size
- To: mathgroup at smc.vnet.net
- Subject: [mg83940] Re: Partition a list into sublists of unequal size
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Wed, 5 Dec 2007 07:08:02 -0500 (EST)
- Organization: Uni Leipzig
- References: <fj37cv$hq0$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
list = {1, 0, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 0, 1, 0};
test = Array[a, {16}];
First /@ Rest[
FoldList[{Take[test, {Min[#1[[2]] + 1, #2], #2}], #2} &, {1, 1},
Flatten@Position[list, 1]]]
may do that.
Regards
Jens
antf wrote:
> Hello,
>
> I have a list that looks like the following:
>
> list={1,0,0,1,0,0,1,1,0,1,0,0,0,0,1,0}
>
> I then find the positions of the 1s in the list:
>
> positions = Flatten@Position[list,1]
>
> {1,4,7,8,10,15}
>
> I then want to partition a third list into sublists so that the first
> sublist is from index 1;;1, the second sublist is from index 2;;4, the
> third sublist is from index 5;;7, the fourth sublist is just element
> 8, etc.
>
> Currently, I use Partition on the positions sublist with overlap as
> in:
>
> Partition[Join[{1},positions],2,1]
>
> {{1,1},{1,4},{4,7},{7,8},{8,10},{10,15}}
>
> I then use this list to partition the target list by Mapping Take to
> each element of this list and adjusting the first index appropriately.
>
> I am sure there must be a simpler way to do this. Can anyone tell me
> how to do this operation?
>
> Thanks,
> Anthony
>