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MathGroup Archive 2007

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Re: sum over i+j+k==n

  • To: mathgroup at smc.vnet.net
  • Subject: [mg84441] Re: [mg84423] sum over i+j+k==n
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Mon, 24 Dec 2007 04:49:01 -0500 (EST)
  • Reply-to: hanlonr at cox.net

n = 4;

Sum[f[i, j, n - i - j], {i, 0, n}, {j, 0, n - i}]

f(0,0,4)+f(0,1,3)+f(0,2,2)+f(0,3,1)+f(0,4,0)+f(1,0,3)+f(1,1,2)+
    f(1,2,1)+f(1,3,0)+f(2,0,2)+f(2,1,1)+f(2,2,0)+f(3,0,1)+f(3,1,0)+f(4,0,0)


Bob Hanlon
]
---- Jack Kennedy <jack at realmode.com> wrote: 
> Hi All,
> I often find myself needing to sum over triples
> (or other tuples) like i,j,k where i+j+k=n. Is there
> a convenient way to write this in Mathematica?
> Thanks,
> Jack
> 
> (version 5.1)
> 



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