Re: how fill PolarPlot?

*To*: mathgroup at smc.vnet.net*Subject*: [mg84434] Re: how fill PolarPlot?*From*: Bill Rowe <readnewsciv at sbcglobal.net>*Date*: Mon, 24 Dec 2007 04:45:16 -0500 (EST)

On 12/23/07 at 4:34 AM, murray at math.umass.edu (Murray Eisenberg) wrote: >I Mathematica 6 I have a PolarPlot, e.g., a 4-leaved rose: >PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}] >How can I fill the inside -- or, what I really want, just the leaf >in the right half-plane -- with some color? >I note that Filling does not seem to be an option for PolarPlot (or >for what would be almost as good, ParametricPlot). >I tried including the following (obtained by converting from : >Prolog->RegionPlot[(x^2 + y^2)^(3/2) <= x^2-y^2, >{x,-0.02,1},{y,-1,1}, Frame->False, AspectRatio->Automatic] >However, that led to a mysterious error message: >$Aborted is not a Graphics primitive or directive. >(Perhaps because of an incompatibility of a Prolog with cartesian >coordinates inside a polar coordinate plot??) I don't know what causes the error message but I do not believe it is the issue of cartesian coordinates versus polar coordinates since the following works with no error messages PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}, AspectRatio -> Automatic, Prolog -> Inset[RegionPlot[(x^2 + y^2)^(3/2) <= x^2 - y^2, {x, -0.02, 1}, {y, -1, 1}, Frame -> False, AspectRatio -> Automatic], {0, 0}, {0, 0}, 1.06]] The only aspect of the the code above I do not understand is the necessity of setting the last size argument to Inset to 1.06. I would have expected this to be 1. But that results in a plot where the right leaf is not completely colored in. -- To reply via email subtract one hundred and four