Re: how fill PolarPlot?

*To*: mathgroup at smc.vnet.net*Subject*: [mg84428] Re: [mg84420] how fill PolarPlot?*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Mon, 24 Dec 2007 04:42:08 -0500 (EST)*References*: <200712230934.EAA03990@smc.vnet.net>

On 23 Dec 2007, at 18:34, Murray Eisenberg wrote: > I Mathematica 6 I have a PolarPlot, e.g., a 4-leaved rose: > > PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}] > > How can I fill the inside -- or, what I really want, just the leaf in > the right half-plane -- with some color? > > I note that Filling does not seem to be an option for PolarPlot (or > for > what would be almost as good, ParametricPlot). > > I tried including the following (obtained by converting from : > > Prolog->RegionPlot[(x^2 + y^2)^(3/2) <= x^2-y^2, {x,-0.02,1}, > {y,-1,1}, > Frame->False, AspectRatio->Automatic] > > However, that led to a mysterious error message: > > $Aborted is not a Graphics primitive or directive. > > (Perhaps because of an incompatibility of a Prolog with cartesian > coordinates inside a polar coordinate plot??) > > -- > Murray Eisenberg murray at math.umass.edu > Mathematics & Statistics Dept. > Lederle Graduate Research Tower phone 413 549-1020 (H) > University of Massachusetts 413 545-2859 (W) > 710 North Pleasant Street fax 413 545-1801 > Amherst, MA 01003-9305 > How about simply: s1 = PolarPlot[Cos[2 theta], {theta, -Pi/4, Pi/4}] /. Line -> Polygon; s2 = PolarPlot[Cos[2 theta], {theta, Pi/2, Pi/2 + Pi/4}] /. Line -> Polygon; s3 = PolarPlot[Cos[2 theta], {theta, 3 Pi/2 - Pi/4, 3 Pi/2}] /.Line -> Polygon; Show[ss, s1, s2, s3] Andrzej Kozlowski

**References**:**how fill PolarPlot?***From:*Murray Eisenberg <murray@math.umass.edu>