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Re: & without #

  • To: mathgroup at
  • Subject: [mg73079] Re: & without #
  • From: Jean-Marc Gulliet <jeanmarc.gulliet at>
  • Date: Thu, 1 Feb 2007 03:47:28 -0500 (EST)
  • Organization: The Open University, Milton Keynes, UK
  • References: <epp68i$cv0$>

Kristen W Carlson wrote:
> Hi,
> From Built-in Functions/Cases, here is this (undocumented?) usage of &
> without #:

Nothing really undocumented here. The symbol '&' is a shortcut for the 
function *Function*. The symbol '#' is another form for *Slot*.

Now, a pure function may accept parameters (or variables) or may not 
accept parameter. The latter case implies that we cannot use *Slot* or 
the # symbol. Therefore, we cannot call it with specific arguments. This 
does not mean that the function must return or do always the same thing.

To understand the difference, have a look at the full form to both 

> L=Array[Random[Integer,10]&,20]
> {4,5,9,6,8,5,4,0,9,4,5,2,10,6,3,7,4,2,2,8}



Above, we are building an array of /functions/ that accept no argument, 
yet return some random values.

% // ReleaseHold // Trace

[output deleted]

> Here is what happens without the &:
> L=Array[Random[Integer,10],20]
> {3[1],3[2],3[3],3[4],3[5],3[6],3[7],3[8],3[9],3[10],3[11],3[12],3[13],3[
>  14],3[15],3[16],3[17],3[18],3[19],3[20]}



Above, we are building an array of random values.

% // ReleaseHold // Trace

[output deleted]

> Can someone who understands this please explain as completely as you
> can, including how & and # work
> together, given the behavior of & alone. And is this documented anywhere?
> This might help and I also post it to help illuminate for those who
> haven't seen this & usage; it is from Andrzej a while ago (Andrzej I
> hope you don't mind):
> In general it means a constant function. For example 3& will return 3
> with any argument. But the are at least two "special" functions,
> which will work like "variable constants" when used in this way. One
> of them is Random[]& (and various variants of it). Another is Unique
> [symbol]&, which on every evaluation will produce a unique name based
> on "symbol".

Hope this helps.


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