Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?

*To*: mathgroup at smc.vnet.net*Subject*: [mg73534] Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?*From*: "dimitris" <dimmechan at yahoo.com>*Date*: Wed, 21 Feb 2007 01:48:51 -0500 (EST)*References*: <erelp9$7mm$1@smc.vnet.net>

On Feb 20, 1:24 pm, "David W.Cantrell" <DWCantr... at sigmaxi.net> wrote: > I hope I've just overlooked something very simple. > I want to transform ArcSinh[2]/ArcCsch[2] to 3, using just "knowledge" > already implemented in Mathematica. I tried FullSimplify first, and it > doesn't help. I tried several other things. For example, > > TrigToExp[ArcSinh[2]/ArcCsch[2]] yields > > Log[2 + Sqrt[5]]/Log[1/2 + Sqrt[5]/2]. > > But then how should we transform that to 3? > > David Not exactly what you want but I think it deserves to be mentioned In[50]:= FullSimplify[ArcSinh[2]/ArcCsch[2] - 3] Out[50]= 0 Regards Dimitris