Re: split

• To: mathgroup at smc.vnet.net
• Subject: [mg73634] Re: split
• From: "dkr" <dkrjeg at adelphia.net>
• Date: Fri, 23 Feb 2007 04:42:27 -0500 (EST)
• References: <erjo7l\$nrf\$1@smc.vnet.net>

```On Feb 22, 4:36 am, Arkadiusz.Ma... at gmail.com wrote:
> Hi,
>
> I want to split a list, say
>
> z = {1, 3, 2, 6, 4, 7, 5,1,7};
>
> into sublist of elements that are less or equal 3.
>
> so I want to obtain
>
> {{1,3,2},{6,4,7,5},{1},{7}}
>
> How to do it? Probably by applying Split, but what to put in Test?
>
> Split[z,#<=3&] gives :
>
> {{1, 3, 2, 6}, {4}, {7}, {5}, {1, 7}}
>
> Why 6 was put in first sublist together with 1, 3, and 2 since 6>3 and
> should be together with 4 in the second sublist?
>
> Thanks,
>
> Arek

Arek,

>From your description of what you want to obtain, it appears that you
want to split your list into runs of elements that are all less than
or equal to 3, or are all greater than 3.

In[8]:=
z = {1, 3, 2, 6, 4, 7, 5,1,7};
Split[z,(#1<=3&&#2<=3)||(#1>3&&#2>3)&]

Out[9]=
{{1,3,2},{6,4,7,5},{1},{7}}

The problem with your use of Split is that your test has only one
variable.  Effectively, what your test is requiring for any pair of
adjacent elements is that the first element of the pair be less than
or equal to 3, while the second element can be anything.  Thus the
adjacent pair (2,6) satisfies your test, and the 6 gets put in the
same sublist as the 2.

dkr

```

• Prev by Date: Fw: Maclaurin series for ArcCosh[x]
• Next by Date: Re: ReplaceList and //.
• Previous by thread: Re: split
• Next by thread: Re: split