Re: ContainsQ ?
- To: mathgroup at smc.vnet.net
- Subject: [mg72582] Re: ContainsQ ?
- From: Peter Pein <petsie at dordos.net>
- Date: Wed, 10 Jan 2007 03:15:06 -0500 (EST)
- References: <eo00nr$kma$1@smc.vnet.net>
Chris Chiasson schrieb: > Is there something like ContainsQ that means !FreeQ? > Hi Chris, ContainsQ = MemberQ[#1, #2, Infinity, Heads -> True]& should do it. Peter