Re: Segregating the elements of a list based on given lower and upper bounds

*To*: mathgroup at smc.vnet.net*Subject*: [mg77311] Re: [mg77205] Segregating the elements of a list based on given lower and upper bounds*From*: DrMajorBob <drmajorbob at bigfoot.com>*Date*: Wed, 6 Jun 2007 07:27:57 -0400 (EDT)*References*: <30655226.1181096377426.JavaMail.root@m35>*Reply-to*: drmajorbob at bigfoot.com

Clear[inbounds] inbounds[{low_?NumericQ, high_?NumericQ}][x_?NumericQ] := low <= x <= high inbounds[{low_?NumericQ, high_?NumericQ}, x_List] := Select[x, inbounds[{low, high}]] inbounds[x_List, y_List] := inbounds[#, x] & /@ y Length /@ inbounds[a, b] {1, 1, 0, 1, 2} Bobby On Tue, 05 Jun 2007 05:58:10 -0500, R.G <gobiithasan at yahoo.com.my> wrote= : > Hi Mathgroup members, > > Say, I have a list with the following elements: > > A={6.32553, 7.09956, 8.56784, 16.1871, 15.3989, 17.2285, 7.40711, \ > 14.8876, 19.9068, 10.0834} > > and I have the following list with each {xvalue, yvalue}={lower boun= d, > upper bound}: > B={{0, 7}, {8, 10}, {11, 12}, {13, 15}, {16, 18}} > > How can I segregate values in A according to lower bound and upper > bound from B and find the number number of occurrence ?For example: > {0,7}={6.32553}, thus the number of occurrence is 1. > {8, 10}={7.09956,7.40711,8.56784}, the number of occurrence is 3. > {11,12}=None, the number of occurrence is 0. > > The code should be able work for any number Length[A] and Length[B]. > Any suggestion please? > Thank you, > R.G > > > -- = DrMajorBob at bigfoot.com