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Re: on a pure function for a list of integrals
*To*: mathgroup at smc.vnet.net
*Subject*: [mg77333] Re: on a pure function for a list of integrals
*From*: "Jean-Marc Gulliet" <jeanmarc.gulliet at gmail.com>
*Date*: Thu, 7 Jun 2007 03:38:57 -0400 (EDT)
*References*: <f43gpj$2k7$1@smc.vnet.net> <4665D6FB.9070505@gmail.com>
On 6/6/07, Ruth <ruth.lazkoz at ehu.es> wrote:
> Thanks, Jean-Marc, you suggest
>
> f = Block[{x, a = #1, b = #2},
> (NIntegrate[Sqrt[a*x + b], {x, 0, #1}] & ) /@ #3] & ;
> f[2, 3, {0.1, 0.5, 0.9}]
>
> but I think there are assignments which are never used as
>
> In[1]:= f = Block[{x},
> (NIntegrate[Sqrt[a*x + b], {x, 0, #1}] & ) /@ #3] & ;
> f[2, 3, {0.1, 0.5, 0.9}]
>
> gives me exactly the same result so the bit a = #1, b = #2 seems unnecessary
How much do you bet on that :-)
In[1]:= f =
Block[{x}, (NIntegrate[Sqrt[a*x + b], {x, 0, #1}] & ) /@ #3] & ;
f[2, 3, {0.1, 0.5, 0.9}]
During evaluation of In[1]:= NIntegrate::inumr:The integrand Sqrt[b+a \
x] has evaluated to non-numerical values for all sampling points in \
the region with boundaries {{0,0.1}}. >>
During evaluation of In[1]:= NIntegrate::inumr:The integrand Sqrt[b+a \
x] has evaluated to non-numerical values for all sampling points in \
the region with boundaries {{0,0.5}}. >>
During evaluation of In[1]:= NIntegrate::inumr:The integrand Sqrt[b+a \
x] has evaluated to non-numerical values for all sampling points in \
the region with boundaries {{0,0.9}}. >>
During evaluation of In[1]:= General::stop:Further output of \
NIntegrate::inumr will be suppressed during this calculation. >>
Out[2]= {NIntegrate[Sqrt[a*x + b], {x, 0, 0.1}],
NIntegrate[Sqrt[a*x + b],
{x, 0, 0.5}], NIntegrate[Sqrt[a*x + b], {x, 0, 0.9}]}
Regards,
Jean-Marc
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