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Re: Iterate Through a List

  • To: mathgroup at smc.vnet.net
  • Subject: [mg77346] Re: Iterate Through a List
  • From: dimitris <dimmechan at yahoo.com>
  • Date: Thu, 7 Jun 2007 03:45:40 -0400 (EDT)
  • References: <f4697t$3ps$1@smc.vnet.net>

Nick you have sent the message various times.
There are many responses.
With the enormous number of messages that "attack"
the moderator it is obvious that it control everything!
Difficult task indeed.

Keep in mind that this forum (good or bad? You can see a glass with
water up to the middle, half empty or half fuel; but
see the number of spams that appeared in another forums
and you will see that it is good) is MODERATED.
The messages do not appear immediately like other forums.
They will need some time (ussually a day). So
do not send a message more than one time!

With best regards
and hope that I didn't
sound elitistic

Dimitris


 /  Nick       :
> Hello! I'm (somewhat) new to Mathematica and I  need help to iterating
> through a list and counting the occurrence of a number.
>
> My list looks like:
>
> {{1,0},{1,1},{2,x+x^2+x^4},{2,1+x+x^2+x^4},{4,x+x^2},{4,1+x+x^2},{4,x+
> \
> x^4},{4,1+x+x^4},{4,x^2+x^4},{4,1+x^2+x^4},{4,x^3+x^4},{4,1+x^3+x^4},
> {\
> 4,x+x^2+x^3+x^4},{4,1+x+x^2+x^3+x^4},{5,x+x^3},{5,1+x+x^3},
> {5,x^2+x^3}\
> ,{5,1+x^2+x^3},{5,x+x^3+x^4},{5,1+x+x^3+x^4},{5,x^2+x^3+x^4},{5,1+x^2+
> \
> x^3+x^4},{8,x},{8,x^2},{8,x^3},{8,x^4},{8,1+x},{8,1+x^2},{8,1+x^3},
> {8,\
> x+x^2+x^3},{8,1+x+x^2+x^3},{8,1+x^4}}
>
> The number that I would need to keep track of is the first in each sub-
> list.
>
> So for the first couple {{1,0},{1,1},{2,x+x^2+x^4},{2,1+x+x^2+x^4},{4,x
> +x^2},........
>
> I would need to keep track of 1,1,2,2,4........
>
> It will not always be 1,2,4,5,8's.  The numbers may be completely
> different on each pass.  Each sublist may be composed of more items
> but the number that I need to keep track of will always be the 1st in
> the sub-list.  Any help or suggestions that you can give me will be
> greatly appreciated.  Thanks so much!
> -Nick



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