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Re: NDSolve, Loop, Table, Plot

  • To: mathgroup at smc.vnet.net
  • Subject: [mg77616] Re: NDSolve, Loop, Table, Plot
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Thu, 14 Jun 2007 05:15:06 -0400 (EDT)
  • References: <f4olu9$7as$1@smc.vnet.net>

Hi,

you can make a function, that take the parameters of
your ode as arguments, something like


sol[omega_] :=
  Module[{f, y, x},
   f = y[x] /.
     NDSolve[{y''[x] + omega^2*y[x] == 0, y[0] == 0, y'[0] == 1},
       y[x], {x, 0, 2 Pi}][[1]];
   Table[{x, f}, {x, 0., 2 Pi, 2 Pi/128}]
   ]

and

ListPlot[{sol[1], sol[2], sol[3]}]

will do that or you can define Rule[]s for the parameter

NDSolve[{y''[x] + omega^2*y[x] == 0, y[0] == 0, y'[0] == 1},
   y[x], {x, 0, 2 Pi}] /. {{omega -> 1}, {omega -> 2}, {omega -> 3}}

Regards
   Jens

Solver wrote:
> Hi,
> 
> I have a system of 3 differential equations and I would like to
> numerically solve them for different values of one parameter (e.g., p1
> = 0.5, 0.6, 0.7, 0.8, etc). Then, I want to 1) make a table for the
> results of B0[200], B1[200], and B2[200] for all values of p1 and 2)
> make plots of B0, B1, B2 through time for the different values of p1.
> Below is the code I tried. The table seems to work sometimes but when
> I run the code multiple times, the output is the same for all values
> of p1 (i.e., {{3.99315, 3.99315, 3.99315, 3.99315, 3.99315, 3.99315},
> {
>     0.0813405, 0.0813405, 0.0813405, 0.0813405, 0.0813405,
>    0.0813405}, {0.021349, 0.021349, 0.021349, 0.021349, 0.021349,
> 0.021349}}. I don't understand why?
> The Plot function gives me multiple plots but they are always the
> same, so it is not drawing plots for the different values of p1.
> 
> J = 1;
> r0 = 0.2;
> r1 = 0.2;
> r2 = 0.2;
> p1 = 0.1;
> 
> dB0 = J - r0*B0[t] - B0[t]*B1[t];
> dB1 = p1*B0[t]*B1[t] - r1*B1[t] - B1[t]*B2[t];
> dB2 = p2*B1[t]*B2[t] - r2*B2[t];
> 
> A = Flatten[Map[({B0[200], B1[200], B2[200]} /. # ) &,
> sol = Table[NDSolve[{B0'[t] == dB0, B1'[t] == dB1, B2'[t] == dB2,
> B0[0] == 1, B1[0] == 1, B2[0] == 1}, {B0, B1, B2},
> {t, 0, 200}], {p1, 0.5, 1, 0.1}]], 1] // Transpose
> Export["A.csv", A];
> Do[Plot[Evaluate[{B0[t], B1[t], B2[t]} /. sol, {t, 0, 200}, PlotStyle -
> {{RGBColor[1, 0, 0]}, {RGBColor[0, 1, 0]}, {RGBColor[0, 0, 1]}}]],
> {p1, 0.5, 1, 0.1}]
> 
> Thanks!
> 
> 


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