Re: Re: extracting fractional powers of series expansion?
- To: mathgroup at smc.vnet.net
- Subject: [mg78324] Re: [mg78257] Re: extracting fractional powers of series expansion?
- From: DrMajorBob <drmajorbob at bigfoot.com>
- Date: Thu, 28 Jun 2007 04:28:51 -0400 (EDT)
- References: <26396889.1182938859211.JavaMail.root@m35>
- Reply-to: drmajorbob at bigfoot.com
Just that it doesn't always work:
SeriesCoefficient[x!, {x, Infinity, 5/2}]
SeriesCoefficient[x!, {x, \[Infinity], 5/2}]
Bobby
On Wed, 27 Jun 2007 04:22:32 -0500, chuck009 <dmilioto at comcast.com> wrote:
> What's wrong with just using the negative power in SeriesCoefficient:
>
> sval = Series[1/(x*(x^2*(1 - x^3))^(1/3)), {x, 0, 10}]
>
> SeriesCoefficient[sval, -5/3]
>
>
--
DrMajorBob at bigfoot.com
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