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MathGroup Archive 2007

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Re: Re: extracting fractional powers of series expansion?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg78324] Re: [mg78257] Re: extracting fractional powers of series expansion?
  • From: DrMajorBob <drmajorbob at bigfoot.com>
  • Date: Thu, 28 Jun 2007 04:28:51 -0400 (EDT)
  • References: <26396889.1182938859211.JavaMail.root@m35>
  • Reply-to: drmajorbob at bigfoot.com

Just that it doesn't always work:

SeriesCoefficient[x!, {x, Infinity, 5/2}]

SeriesCoefficient[x!, {x, \[Infinity], 5/2}]

Bobby

On Wed, 27 Jun 2007 04:22:32 -0500, chuck009 <dmilioto at comcast.com> wrote:

> What's wrong with just using the negative power in SeriesCoefficient:
>
> sval = Series[1/(x*(x^2*(1 - x^3))^(1/3)), {x, 0, 10}]
>
> SeriesCoefficient[sval, -5/3]
>
>



-- 

DrMajorBob at bigfoot.com


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