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Re: Hold and Equal
*To*: mathgroup at smc.vnet.net
*Subject*: [mg73799] [mg73799] Re: Hold and Equal
*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
*Date*: Fri, 2 Mar 2007 05:58:03 -0500 (EST)
*Organization*: Uni Leipzig
*References*: <erufqm$s7j$1@smc.vnet.net> <200702271048.FAA24024@smc.vnet.net> <es3ib9$nus$1@smc.vnet.net>
*Reply-to*: kuska at informatik.uni-leipzig.de
Hi,
and
SetAttributes[formEquation, HoldFirst]
formEquation[expr_, op_] := HoldForm[expr = z] /. z -> op[expr]
will work as expected.
Regards
Jens
Murray Eisenberg wrote:
> Aha! I believe this approach _almost_ allows me to accomplish what I
> was REALLY trying to accomplish. It certainly works in the example I
> gave. If I encapsulate this in a function...
>
> formEquation[expr_, op_]:= HoldForm[expr=z]/.z\[Rule]op[expr]
>
> ... then
>
> formEquation[(a+b)^2,Identity]
>
> will produce exactly what I want.
>
> However, if I try something like the example I was really after (which I
> didn't mention in my original post, since I gave something simpler), it
> works in the direct version...
>
> HoldForm[Integrate[x^2,x] = z] /. z\[Rule]Integrate[x^2,x]
>
> but not with the encapsulating function:
>
> formEquation[Integrate[x^2, x], Identity]
>
> The latter produces the equation
>
> x^3/3 = x^3/2
>
> whereas I want the left-hand side to be the unevaluated integral expression.
>
> You can tell I'm struggling with Hold! (One of the "last frontiers" in
> my Mathematica education.)
>
> bghiggins at ucdavis.edu wrote:
>> Murray,
>>
>> Try this
>>
>>
>> HoldForm[(a + b)^2 = z] /. z -> Expand[(a + b)^2]
>>
>>
>> (a + b)^2 = a^2 + 2*a*b + b^2
>>
>> Cheers,
>>
>> Brian
>>
>>
>>
>> On Feb 26, 3:20 am, Murray Eisenberg <mur... at math.umass.edu> wrote:
>>> How can I produce in an Output cell (under program control) an
>>> expression like the following,
>>>
>>> (a+b)^2 = a^2+ 2 a b + b^2
>>>
>>> where instead of the usual Equal (==) I get a Set (=), as in traditional
>>> math notation? I want to input the unexpanded (a+b)^2 and have the
>>> expansion done automatically.
>>>
>>> Of course, I can try something like the following:
>>>
>>> (a+b)^2 == Expand[(a+b)^2])
>>>
>>> So how do I convert the == to =? Of course
>>>
>>> ((a + b)^2 == Expand[(a + b)^2]) /. Equal -> Set
>>>
>>> gives a Set::write error. And
>>>
>>> (Hold[(a + b)^2 == Expand[(a + b)^2]]) /. Equal -> Set
>>>
>>> doesn't actually evaluate the Expand part and leaves the "Hold" wrapper.
>>>
>>> --
>>> Murray Eisenberg mur... at math.umass.edu
>>> Mathematics & Statistics Dept.
>>> Lederle Graduate Research Tower phone 413 549-1020 (H)
>>> University of Massachusetts 413 545-2859 (W)
>>> 710 North Pleasant Street fax 413 545-1801
>>> Amherst, MA 01003-9305
>>
>>
>
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