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Re: Re: Means


Mean[Drop[list, IntegerPart[Length[list]/2]][[All, 2]]]


Bob Hanlon

---- "JGBoone at gmail.com" <JGBoone at gmail.com> wrote: 
> Yeah Bob that line you gave me does the same as N[Mean[Map[Last,
> list]]]. It goes to the second part of the pair and takes the average
> of all. I want to take only the average of the last half of the last
> half. So i have 3000 pairs that look like {a,b}
> i've got a way to take the means of all the b's in list of 3000. but i
> want to take the mean's of the last 1500 b's.



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