Re: Re: Means

*To*: mathgroup at smc.vnet.net*Subject*: [mg73970] Re: [mg73939] Re: Means*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Sat, 3 Mar 2007 23:51:40 -0500 (EST)*Reply-to*: hanlonr at cox.net

Mean[Drop[list, IntegerPart[Length[list]/2]][[All, 2]]] Bob Hanlon ---- "JGBoone at gmail.com" <JGBoone at gmail.com> wrote: > Yeah Bob that line you gave me does the same as N[Mean[Map[Last, > list]]]. It goes to the second part of the pair and takes the average > of all. I want to take only the average of the last half of the last > half. So i have 3000 pairs that look like {a,b} > i've got a way to take the means of all the b's in list of 3000. but i > want to take the mean's of the last 1500 b's.