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Re: Replacement question


in your example
1 + a + b + c /. a + b -> x
1 + c + x

but for  more complicates cases, you have to use
more complicated patterns.


Brian Beckage wrote:
> I apologize for this very basic question.  I understand how to use /. 
> {} to replace a  variable with a more complex expression, e.g., x-> 
> y+z.  Can one move in the opposite direction to replace all 
> occurrences of y+z with x?   myExpression/.{y+z->x} does not seem to 
> work.
> Thank you for your help,
> Brian

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