Re: Replacement question

*To*: mathgroup at smc.vnet.net*Subject*: [mg74186] Re: Replacement question*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>*Date*: Wed, 14 Mar 2007 03:40:48 -0500 (EST)*Organization*: Uni Leipzig*References*: <et5nnh$jhk$1@smc.vnet.net>*Reply-to*: kuska at informatik.uni-leipzig.de

Hi, in your example 1 + a + b + c /. a + b -> x gives 1 + c + x but for more complicates cases, you have to use more complicated patterns. Regards Jens Brian Beckage wrote: > I apologize for this very basic question. I understand how to use /. > {} to replace a variable with a more complex expression, e.g., x-> > y+z. Can one move in the opposite direction to replace all > occurrences of y+z with x? myExpression/.{y+z->x} does not seem to > work. > > Thank you for your help, > Brian > > >