Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2007
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: About function to evaluation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg74521] Re: About function to evaluation
  • From: dh <dh at metrohm.ch>
  • Date: Fri, 23 Mar 2007 19:19:47 -0500 (EST)
  • References: <ett7mp$ifv$1@smc.vnet.net>


Hi Evanescence,

f[x_, y_] := 2*x + 3*y;

data = {{1, 2, 0}, {2, 3, 0}, {4, 1, 0}, {6, 3, 0}, {1, 3, 0}};

data = ({#1[[1]], #1[[2]], f[#1[[1]], #1[[2]]]} & ) /@ data;

TableForm[data, TableHeadings -> {None, {"x", "y", "f[x,y]"}}]

Daniel



Evanescence wrote:

> Hello Dear all:

> My questions are as follows:

> First I definite a function is f[x_,y_]:=2x+3y

> Then I have a list is data={{1,2,0},{2,3,0},{4,1,0},{6,3,0},{1,3,0}}

> For example{y,x,z}={1,2,0}    {y,x,z}={2,3,0}  {y,x,z}={4,1,0}

> {y,x,z}={6,3,0} {y,x,z}={1,3,0}

> I want to take the list data to the function to get the function

> values.

> Then express the form as follows at last

> 

>    x     y     f[x,y]

>    2     1       7

>    3     2      12

>    1     4      14

>    3     6      24

>    3     1       9

> 

> PS: The z values is zero overall.

> Please tell me how to get the function values in the list

> Thank you very much

> Evanescence 2007 03 21

> 

> 




  • Prev by Date: Re: About function to evaluation
  • Next by Date: CoefficientList
  • Previous by thread: Re: About function to evaluation
  • Next by thread: Re: About function to evaluation