Re: Is this a problem in mathematica?

*To*: mathgroup at smc.vnet.net*Subject*: [mg74643] Re: Is this a problem in mathematica?*From*: dh <dh at metrohm.ch>*Date*: Thu, 29 Mar 2007 02:35:11 -0500 (EST)*References*: <eud3g1$l0t$1@smc.vnet.net>

Hi, Minimize searches the global minimum and if you read the manual, there you find: "Even if the same minimum is achieved at several points, only one is returned". To get both x values, you can e.g. write the distance as a function of x: dist = x^2 + ((x^2 + 1) - 2)^2 and search extremal points like: Solve[{D[dist,x]==0,D[dist,y]==0},{x}] Daniel traz wrote: > Let's say I wanna solve this problem: > > Determine point(s) on y = x^2 +1 that are > closest to (0,2). > > So in mathematica: > > minDist = (x - 0)^2 + (y - 2)^2; > Minimize[minDist, y == 1 + x^2, {x, y}] > > Output will give you: x -> -1/Sqrt[2], y -> 3/2 > > but x also has another answer: +1/Sqrt[2]. Is this a problem in mathematica or can my code be changed to output the other value of x for the minimum distance? >