       Re: Is this a problem in mathematica?

• To: mathgroup at smc.vnet.net
• Subject: [mg74643] Re: Is this a problem in mathematica?
• From: dh <dh at metrohm.ch>
• Date: Thu, 29 Mar 2007 02:35:11 -0500 (EST)
• References: <eud3g1\$l0t\$1@smc.vnet.net>

```
Hi,

Minimize searches the global minimum and if you read the manual, there

you find: "Even if the same minimum is achieved at several points, only

one is returned".

To get both x values, you can e.g. write the distance as a function of

x: dist = x^2 + ((x^2 + 1) - 2)^2 and search extremal points like:

Solve[{D[dist,x]==0,D[dist,y]==0},{x}]

Daniel

traz wrote:

> Let's say I wanna solve this problem:

>

> Determine point(s) on y = x^2 +1 that are

> closest to (0,2).

>

> So in mathematica:

>

> minDist = (x - 0)^2 + (y - 2)^2;

> Minimize[minDist, y == 1 + x^2, {x, y}]

>

> Output will give you: x -> -1/Sqrt, y -> 3/2

>

> but x also has another answer: +1/Sqrt. Is this a problem in mathematica or can my code be changed to output the other value of x for the minimum distance?

>

```

• Prev by Date: 2X2 arrays
• Next by Date: Re: comments in import files
• Previous by thread: Re: Is this a problem in mathematica?
• Next by thread: Re: Is this a problem in mathematica?