Re: Re: Is this a problem in mathematica?

*To*: mathgroup at smc.vnet.net*Subject*: [mg74645] Re: [mg74622] Re: Is this a problem in mathematica?*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Thu, 29 Mar 2007 02:36:12 -0500 (EST)*References*: <eud3g1$l0t$1@smc.vnet.net> <200703280935.EAA28877@smc.vnet.net>

On 28 Mar 2007, at 11:35, Johan Gr=F6nqvist wrote: > traz skrev: >> Let's say I wanna solve this problem: >> >> Determine point(s) on y = x^2 +1 that are >> closest to (0,2). >> >> So in mathematica: >> >> minDist = (x - 0)^2 + (y - 2)^2; >> Minimize[minDist, y == 1 + x^2, {x, y}] >> >> Output will give you: x -> -1/Sqrt[2], y -> 3/2 >> >> but x also has another answer: +1/Sqrt[2]. Is this a problem in >> mathematica or can my code be changed to output the other value of = >> x for the minimum distance? >> > > > The help browser page on Minimize says "Even if the same minimum is > achieved at several points, only one is returned. " > > I think the problem might be solved by using FindMinimium, and > starting > from several different points. > > / johan > Even easier: minDist = (x - 0)^2 + (y - 2)^2; Minimize[{minDist, y == 1 + x^2 && x > 0}, {x, y}] {3/4, {x -> 1/Sqrt[2], y -> 3/2}} Andrzej Kozlowski=

**References**:**Re: Is this a problem in mathematica?***From:*Johan Grönqvist <johan.gronqvist@gmail.com>