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Re: Simplification
*To*: mathgroup at smc.vnet.net
*Subject*: [mg75439] Re: Simplification
*From*: dimitris <dimmechan at yahoo.com>
*Date*: Tue, 1 May 2007 03:18:21 -0400 (EDT)
*References*: <f146na$m9e$1@smc.vnet.net>
> oo = Product[Cos[(2^j*Pi)/1023], {j, 0, 9}]/Product[Cos[(2^j*Pi)/1025],=
{j, 0, 9}];
Having received a couple of responses mentioning that
N@oo
-1
I think I ought to restate my queries.
My basic question is how can someone SIMPLIFY oo to -1.
That is, I want a series of steps including functions like
(Full)Simplify,
RootReduce, TrigToExp, TrigReduce etc.
Note that in another CAS (during to the well known policy of this
forum I can't
mention its name) someone working as follows can take the desired
simplification.
Product(cos(Pi*2^j/1023), j= 0..9)/ Product(cos(Pi*2^j/1025), j=
0=2E.9):
p:=value(%);
convert(p, sin);
simplify(%);
Pi 2 Pi 4 Pi 8 Pi 16 Pi
p := - cos(----) cos(----) cos(----) cos(----) cos(-----)
1023 1023 1023 1023 1023
32 Pi 64 Pi 128 Pi 256 Pi 511 Pi
cos(-----) cos(-----) cos(------) cos(------) cos(------)
1023 1023 1023 1023 1023
/ / Pi 2 Pi 4 Pi 8 Pi 16 Pi
/ |cos(----) cos(----) cos(----) cos(----) cos(-----)
/ \ 1025 1025 1025 1025 1025
32 Pi 64 Pi 128 Pi 256 Pi 512 Pi \
cos(-----) cos(-----) cos(------) cos(------) cos(------)|
1025 1025 1025 1025 1025 /
512 Pi 1022 Pi Pi
sin(------) sin(-------) sin(----)
1023 1023 1025
- ----------------------------------
Pi 511 Pi 1024 Pi
sin(----) sin(------) sin(-------)
1023 1023 1025
-1
However, no matter what have I tried I was not able to find a
simplification procedure
in Mathematica.
The expression
o1=-(Sin[(512*Pi)/1023]*Sin[(1022*Pi)/1023]*
Sin[Pi/1025])/(Sin[Pi/1023]*Sin[(511*Pi)/
1023]*Sin[(1024*Pi)/1025])
which appeared by application of the function convert of the other CAS
can be simplified to -1 in Mathematica
-(Sin[(512*Pi)/1023]*Sin[(1022*Pi)/1023]*
Sin[Pi/1025])/(Sin[Pi/1023]*Sin[(511*Pi)/
1023]*Sin[(1024*Pi)/1025]) // TrigToExp // ExpandAll //
Together
-1
So, the question may be put how someone can write oo as o1.
(although I am sure Andrzej Kozlowski will not be very fond of this
idea!)
My second query is how can someone show that oo==-1 (or oo-1==0) is
equal to true.
Even I consider this much more simpler task, again my (any!) knowledge
of Mathematica
give again pure results.
Thanks in advance for any response.
I really appreciate any help I got and will (I hope!) get
Dimitris
=CF/=C7 dimitris =DD=E3=F1=E1=F8=E5:
> This appeared in another forum.
>
> (Converting to Mathematica InputForm.)
>
> In[2]:=
> oo = Product[Cos[(2^j*Pi)/1023], {j, 0, 9}]/Product[Cos[(2^j*Pi)/
> 1025], {j, 0, 9}];
>
> The expression can be simplified to -1.
>
> Indeed, adopted by someone's reply, in another CAS, we simply have
>
> Product(cos(Pi*2^j/1023), j= 0..9)/ Product(cos(Pi*2^j/1025), j=
> 0..9):
> p:=value(%):
> convert(p, sin):
> simplify(%);
> -1
>
> However, no matter what I tried I was not able to succeed in
> simplifying above expression
> to -1 with Mathematica, in reasonable time. Futhermore, even the much
> more simpler of
> showing oo==-1 didn't work.
>
> So I would really appreciate if someone pointing me out:
> 1) A way to show (in Mathematica!) that oo is simplified to -1
> 2) That the equality oo==-1 (or oo-1==0 alternatively) can be
> simplified
> to True.
>
> Any ideas?
>
> BTW, I found the function convert of the other CAS, very useful.
> Has anyone implementated a similar function in Mathematica?
> (I ain't aware of a Mathematica built-in function, similar to convert
> from the other CAS.)
>
> Dimitris
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